All categories

3 years ago

Superman takes 8 seconds to stop a runway train over a distance of 58 m using a power of

Physics

1 answer:

elena-14-01-66 [18.8K]3 years ago

5 0

Answer:

Workdone = 600 Kilojoules

Explanation:

Given the following data:

Time = 8 seconds

Power = 75,000 Watts

Distance = 58 m

To find the work done;

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

$Power = \frac {Energy}{time}$

Thus, work done is given by the formula;

Workdone = power * time

Workdone = 75000 * 8

Workdone = 600,000 = 600 KJ

You might be interested in

Potential energy is the energy an object has because of its

Naya [18.7K]

Radiation compared to other potential

3 0

2 years ago

A small pebble and one large boulder start at the same height and begin rolling down the side of a mountain. Which object would

vitfil [10]

Answer:

The small pebble

Explanation:

Since the potential energy, P.E lost equals kinetic energy, K.E gained,

P.E = K.E

P.E = mgh = K.E

So, K.E = mgh where g = acceleration due to gravity and h = height of drop

Since h and g are constant

K.E ∝ m

So, the kinetic energy of the object is directly proportional to its mass. Thus, the object with the smaller mass has the lesser kinetic energy.

Since the object with the smaller mass is the small pebble, so the small pebble would have less kinetic energy as it crashes on the road at the bottom of the mountain.

8 0

3 years ago

Water is considered to be

Natalka [10]

Answer: the thing that brings you life- h2o- idrk the question but if this helps your welcome ^-^have a good day

Explanation:

3 0

3 years ago

A playground carousel is rotating counterclockwise about its center on frictionless bearings. A person standing still on the gro

Shtirlitz [24]

Answer:

1.94601 rad/s

Explanation:

$I_1$ = Moment of inertia of carousel = 124 kgm²

$\omega_1$ = Angular speed of carousel = 3.5 rad/s

$\omega_2$ = Angular speed of person

r = Radius of carousel = 1.53 m

m = Mass of person = 42.3 kg

Moment of inertia of person

$I_2=mr^2\\\Rightarrow I_2=42.3\times 1.53^2\\\Rightarrow I_2=99.02007\ kgm^2$

As the angular momentum is conserved in the system

$I_1\omega_1=(I_1+I_2)\omega_2\\\Rightarrow \omega=\frac{I_1\omega_1}{(I_1+I_2)}\\\Rightarrow \omega_2=\frac{124\times 3.5}{(124+99.02007)}\\\Rightarrow \omega_2=1.94601\ rad/s$

The angular speed of the carousel after the person climbs aboard is 1.94601 rad/s

5 0

3 years ago

A(n) 19000 kg freight car is rolling along a track at 1.5 m/s. Calculate the time needed for a force of 2600 N to stop the car.

garik1379 [7]

Answer: 10.96secs

Explanation:

According to newton's second law

Force = mass × acceleration

F = ma

F = m(v-u)/t

Cross multiplying we have

Ft = m(v-u)

t = m(v-u)/F

Given F = 2600N m = 19,000kg v = 1.5m/s u = 0m/s

Substituting this values in the formula for the time we have

t = 19000(1.5-0)/2600

t = 28,500/2600

t= 10.96secs

7 0

3 years ago