All categories

2 years ago

Jeffrey walked 1/2 Mile on Monday and jogged 2/3 Mile on Tuesday how far did he walk and jog on Monday And Tuesday combined

Mathematics

2 answers:

dedylja [7]2 years ago

8 0

Answer: Answer in Mixed Number Form: 1 1/6

Exact Form: 7/6

Hope this helped.

Step-by-step explanation:

Artemon [7]2 years ago

4 0

Answer:

7/6 or 1 1/6

Step-by-step explanation:

First I would change both numbers to have the same denominator. I would change the thirds to sixes and the halves into sixes as well/ So I multiply 2x2 for the top to get 4 and 3x2 to get 6. Then I would multiply 2x3 to get 6 and 1x3. Then I would have add 4/6 and 3/6 to get 7/6. If you need it in number form I would simplify it to get 1 1/6

You might be interested in

A theater has 418 seats put in rows of 19 seats each. how many rows are in the theater

GarryVolchara [31]

Answer:

Step-by-step explanation:

418 divided by 19 is 22.

8 0

2 years ago

Read 2 more answers

The diameter of the pan is 9 inches. What is the approximate circumference of a lid that will fit his frying pan? (Use 3.14 for

konstantin123 [22]

Answer:

28.26

Step-by-step explanation:

the equation for circumference is 2pi*r or pi*d

3.14*9 (the diametre) is 28.26

Answer 28.26

6 0

2 years ago

A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic

goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event E $_{i}$ , of the sample space S, given that another event A has already occurred is:

$P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}$

The law of total probability states that, if events E₁, E₂, E₃... are parts of a sample space then for any event A,

$P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}$

Denote the events as follows:

X = fetus have a chromosome abnormality.

Y = the test is positive

The information provided is:

$P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85$

Using the above the probabilities compute the remaining values as follows:

$P(X^{c})=1-P(X)=1-0.04=0.96$

$P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10$

$P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15$

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

$P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})$

$=(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82$

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

$P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}$

$=\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}$

$=0.20$

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0

3 years ago

If f(x)=x2-2x-8 and g(x)=1/4x-1 for which value of x is f(x)=g(x)

fomenos

$f(x)=x^2-2x-8;\ g(x)=\dfrac{1}{4}x-1\\\\f(x)=g(x)\iff x^2-2x-8=\dfrac{1}{4}x-1\qquad\text{multiply both sides by 4}\\\\4x^2-8x-32=x-4\qquad\text{subtract x from both sides}\\\\4x^2-9x-32=-4\qquad\text{add 4 to both sides}\\\\4x^2-9x-28=0\\\\4x^2-16x+7x-28=0\\\\4x(x-4)+7(x-4)=0\\\\(x-4)(4x+7)=0\iff x-4=0\ \vee\ 4x+7=0\\\\x=4\ \vee\ 4x=-7\\\\\boxed{x=4\ \vee\ x=-\dfrac{7}{4}}$

6 0

3 years ago

The temperature in the Arctic Circle at 9:00am was 22.8° below zero. By 6:00pm on the same day, the temperature had decreased by

rosijanka [135]

4.65 is the new temperature.

8 0

3 years ago