Answer:
Length 10, Width 20, Area 200
Step-by-step explanation:
Answer:
p=-6
q=3
Step-by-step explanation:
5p-3q=-39
-2p-3q=3
Multiply the second equation by -1
2p +3q = -3
Add the first equation and the modified second equation
5p-3q=-39
2p +3q = -3
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7p = -42
Divide by 7
7p/7 = -42/7
p = -6
Now we can find q
2p +3q = -3
2(-6) +3q = -3
-12 +3q = -3
Add 12 to each side
-12+12 +3q = -3+12
3q = 9
Divide by 3
3q/3 = 9/3
q=3
Answer:
4cm^2
Step-by-step explanation:
First we need to find the length of the height of the triangle using Pythagoras:
a^2+b^2=c^2 (Substitute in what we have)
a^2+3√2(^2)=2√5(^2) = a^2 + 18 = 20 -> 20-18=2 √2=BD
Now we can find the area:
AD+DC= 3√2 + √2 = 4√2 x √2 = 8/2 = 4
