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Elan Coil [88]
3 years ago
8

I need help understanding square roots

Mathematics
1 answer:
Vlad [161]3 years ago
6 0

I wonder if you mean to write \sqrt[3]{256} in place of 3\sqrt{256}...

If you meant what you wrote, then we have

\sqrt{256}=\sqrt{16^2}=16

3\sqrt{256}=3\cdot16=48

If you meant to write \sqrt[3]{256} (the cube root of 256), then we could go on to have

\sqrt[3]{256}=\sqrt[3]{16^2}=\sqrt[3]{(4^2)^2}=\sqrt[3]{4^4}=\sqrt[3]{4^3\cdot4}=4\sqrt[3]4

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A number is between 41 and 46 . it has prime factors of 2 and 11 what is the number ​
AfilCa [17]

44 because it goes into 2 and also goes into 11

4 0
3 years ago
Abir walks four twelfths of a mile to school. Nadia walks two twelfths of a mile to school. How much farther does Abir walk than
exis [7]

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Step-by-step explanation:

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4 0
3 years ago
Write an equation to match each graph:
Makovka662 [10]

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y=-|x+1|+1

Step-by-step explanation:

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8 0
3 years ago
In a school, 2/3 the students study a language.
xxTIMURxx [149]

Answer:

4:11

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6 0
2 years ago
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The value of a second-hand car is £8000. Each year it loses 20% of its value at the start of this year. work out its value in 5
Elodia [21]

Answer:

the value in the five years is  £2,621.44

Step-by-step explanation:

The computation of the value in the five years is given below:

= The value of the second car × (1 - losses percentage)^number of years

= £8,000 × (1 - 0.20)^5

= £8,000 × 0.80^5

= £8,000 ×  0.32768

=  £2,621.44

Hence, the value in the five years is  £2,621.44

We simply applied the above formula so that the correct value could come

And, the same is to be considered

7 0
2 years ago
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