A) 42,000m divided by 2 1/3 = 18,000m divide by 1000m to get km = 18km/hr
B) 18,000m divided by 60 to get minutes = 300m divide by 60 to get seconds = 5m/sec.
Answer:
52 is the size of the sample space of this two-stage experiment
$55x5 days= $275
$285.20-275=$10.20
10.20/.15= 68
Answer= 68 miles
The minimum speed will be calculated as follows:
Time taken from Toledo to Elkhart=(8.15-5.45)=2 1/2 hours
Distance=136 miles
thus the speed between Toledo and Elkhart= 136 miles/2.5=54.4 mph
Distance between Toledo and Chicago is 244 miles
Distance between Elkhart and Chicago=244-136=108 miles
time taken to travel between Elkhart and Chicago assuming that I left Elkhart at exactly 8:15 and reach at 10.30:
=10:30-8:15=2.25 hours
thus the speed will be:
speed=(108)/(2.25)=48 mph
Thus for us to get to Chicago by 10:30 a.m we should drive at 48 mph
Step-by-step explanation:
3 to 8= 5
8 to 17= 9
17 to 30= 13
30 to 47= 17
47 to 68= 21
68 to 93= 25
93 to 122= 29
122 to 155= 33
155 to 192= 37
difference is 4
solve by
