Answer:
-3/4 and 1/-2 is the correct answer.
Step-by-step explanation:
Answer:
x ≥ -1
Step-by-step explanation:
Hope this helps
The probability from 1.5 ≤ x ≤ 3 can be calculated by dividing the Area from x=1.5 to x=3 by the total Area of the distribution.
The given distribution is rectangular shaped, so its Area will be = Length x Width = 1 x 3 = 3 square units
From x = 1.5 to x = 3, the length is 1.5 and width is 1. So the area between these two intervals = 1.5 square units.
Thus, <span>P(1.5 ≤ X ≤ 3) = 1.5/3 = 0.5
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A) 
B)In 200 times he can hit 59 times !
<u>Step-by-step explanation:</u>
Here we have , A baseball player got a hit 19 times in his last 64 times at bat. We need to find the following :
a. What is the experimental probability that the player gets a hit in an at bat?
According to question ,
Favorable outcomes = 19
Total outcomes = 64
Probability = (Favorable outcomes)/(Total outcomes) i.e.
⇒ 
⇒ 
b. If the player comes up to bat 200 times in a season, about how many hits is he likely to get?
According to question , In 64 times he hit 19 times . In 1 time there's probability to hit 0.297 times! So ,In 200 times he can hit :
⇒ 
⇒ Hit = 59.36
Therefore , In 200 times he can hit 59 times !