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Ratling [72]
3 years ago
10

38.2834. V1435. 36- 5637. v40. V4141. 214265 43. 12 445 8 -3ja 47. V3248. V4749. V99 50

Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0
No, your answer are wrong (I assume that the question asks to simplify the roots). You can only remove (their square is placed in from of the root and multiplied by it) the numbers from the root that are squares, the lest must stay, like this:

\sqrt{14} = \sqrt{2*7} , no roots are among the factors, nothing can be removed
\sqrt{14} = \sqrt{2*7} , nothing can be removed
-\sqrt{39} = -\sqrt{3*13}nothing can be removed
-\sqrt{56} = -\sqrt{2*2*2*7}=-2\sqrt{14} ,
-\sqrt{77} = -\sqrt{11*7} ,nothing can be removed
\sqrt{41} = \sqrt{41} ,nothing can be removed
\sqrt{21} = \sqrt{3*7} , nothing can be removed
- \sqrt{65} = -\sqrt{5*13} , nothing can be removed
-\sqrt{12} = -\sqrt{2*3*4} =-2\sqrt{4},
\sqrt{13} = \sqrt{13} , nothing can be removed
\sqrt{32} = \sqrt{4*4*2} =4\sqrt{2},
\sqrt{47} = \sqrt{47} , (47 is prime) nothing can be removed
-\sqrt{99} = -\sqrt{9*11}= -3\sqrt{11} ,

































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 Whose solution is:
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 Answer:
 
constants a and b are:
 
a = -8 / 65
 
b = -1 / 65
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answer
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