surface area of the outside of a cube shaped closed-top water tank whose edge length is 7.2 ft, can be solved by solving the area of each face of a cube. since the cube has 6 faces and all the faces are congruent because it all has the same edge.
so the formulaA = 6s^2where s is the edge lengthA = 6 ( 7.2^2)A = 311.04 sq ft.
Answer:
Step-by-step explanation:
Find attached the solution
Answer:
Option 1
Step-by-step explanation:
Arc MK is equal to the sum of arcs ML and LK.
Answer:
1E18 OR 10^18
Step-by-step explanation:
The formula is multiply the length by 1e+18
Answer:
-1/4x² + 3
Step-by-step explanation:
Given that:
Path of sprinkler is modeled by the quadratic function :
w(x) = -1/4(x^2 -12 )
w(x) = height of the water, in meters, at position x
The height of ceiling as a constant or Coefficient = w(x)
Expanding w(x)
-1/4(x^2 -12 )
-1/4 * x² + 1/4 * 12
-1/4x² + 3
The height of ceiling is -1/4x² + 3