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vekshin1
1 year ago
11

Solve with the law of sine

Mathematics
1 answer:
Zinaida [17]1 year ago
5 0

1) Triangle QRT, where q = 32.4 ft, r = 29.8 ft, t = 42.1 ft

No this cannot make a second triangle

2) Triangle ABC, where B = 62°, a = 11.52 m, c = 19.34 m

No this cannot make a second triangle

3) Both of the triangles cannot make a second triangle

<h3>How does law of sine work</h3>

The following is a detailed explanation of the sine law: In a triangle, side "a" divided by angle sine "a" equals side "b" divided by angle sine "b" equals side "c" divided by angle sine "c."

The formula for law of sine is written as

Sine A  a = Sine B/ b = Sine C / c

These law helps in determining the given angles and sides

For the situation given; both cannot be used to make a second triangle

Learn more about conditions Infinite number of triangles at:

brainly.com/question/29637739

#SPJ1

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How much do I need to subtract from 67/10 to make 6
Harrizon [31]

Answer:

0.7

Step-by-step explanation:

67/10 is the same as 6.7 when you subtract the 0.7 you will remain with 6

4 0
2 years ago
Use the properties of exponents to rewrite the expression.<br> (-3yz)(-3yz)(-3yz)(-3yz)
Lera25 [3.4K]

Answer:

Answer is 81y^4z^4

Step-by-step explanation:

The expression is (-3yz) (-3yz) (-3yz) (-3yz).

Since all the four terms have power 1:

(-3yz)^1 (-3yz)^1 (-3yz)^1 (-3yz)^1

We know that we can add the powers if the terms have same base

So,

=(-3yz)^1+1+1+1

=(-3yz)^4

=(-3)^4(y)^4(z)^4.

If the power is an even number than the negative sign changes into positive sign.

=3^4y^4z^4

=81y^4z^4

Thus the answer is 81y^4z^4....

3 0
3 years ago
Suppose f(x) = 6x^2 + 2x − 7 and g(x) = 4x − 3. Find each of the following functions.
FinnZ [79.3K]

Step-by-step explanation:

(f+g)(x) ➡ f(x) + g(x) ➡ 6x^2 + 2x -7 + 4x - 3 =6x^2 + 6x - 10

(f-g)(x) ➡ f(x) - g(x) ➡ 6x^2 + 2x - 7 -4x + 3 = 6x^2 -2x -4

8 0
3 years ago
Javier volunteers in community events each month. He does not do more than five events in a month. He attends exactly five event
mezya [45]

Answer:

The probability of Javier volunteers for less than three a month is 25%

Step-by-step explanation:

According to the questions,

The probability of Javier to attend exactly 5 events :-

P ( x = 5 ) = 25% = \frac{1}{4}

The probability of Javier to attend exactly 4 events :-

P ( x = 4 ) = \frac{1}{4}

The probability of Javier to attend exactly 3 events :-

P ( x = 3 ) = \frac{1}{4}

The probability of Javier to attend exactly 2 events :-

P ( x = 2 ) = \frac{3}{20}

The probability of Javier to attend exactly 1 events :-

P ( x = 1 ) = \frac{1}{20}

The probability of Javier to attend no events :-

P ( x = 0 ) = \frac{1}{20}

Now we have to calculate the probability of Javier volunteers for less than three P ( x < 3 ).

P ( x < 3 ) = P ( x = 0 ) + P ( x = 1 ) + P ( x = 2 )

P ( x < 3 ) = \frac{1}{20} + \frac{1}{20} + \frac{3}{20}   = \frac{1 + 1 + 3}{20}  = \frac{5}{20}  = \frac{1}{4}   = 0.25 = 25 %.

8 0
2 years ago
Can you help me with this question please
Aleksandr-060686 [28]

Answer:

The actual length of the lap = 250 meters

Step-by-step explanation:

∵ The scale factor of the map is 1:1000

∵ The length of the lap on the map is 25 cm

∴ \frac{1}{1000}=\frac{25}{x}

Where x is the actual length of a lap

∴ x = (25 × 1000) ÷ 1 = 25000 cm

∵ 1 meter = 100 centimeter

∴ The actual length of the lap = 25000 ÷ 100 = 250 meters

7 0
3 years ago
Read 2 more answers
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