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1 year ago

Solve with the law of sine

Mathematics

1 answer:

Zinaida [17]1 year ago

5 0

1) Triangle QRT, where q = 32.4 ft, r = 29.8 ft, t = 42.1 ft

No this cannot make a second triangle

2) Triangle ABC, where B = 62°, a = 11.52 m, c = 19.34 m

No this cannot make a second triangle

3) Both of the triangles cannot make a second triangle

The following is a detailed explanation of the sine law: In a triangle, side "a" divided by angle sine "a" equals side "b" divided by angle sine "b" equals side "c" divided by angle sine "c."

The formula for law of sine is written as

Sine A a = Sine B/ b = Sine C / c

These law helps in determining the given angles and sides

For the situation given; both cannot be used to make a second triangle

Learn more about conditions Infinite number of triangles at:

brainly.com/question/29637739

#SPJ1

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gizmo_the_mogwai [7]

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3 years ago

How do I solve f+4/g=6 for f showing my work

V125BC [204]

We have two solutions for this problem based on the given equation.

Answer #1:

If the given equation was:

$f + \frac{4}{g} = 6$

To solve for f, we would need to isolate the "f" on one side of the equation.

In case of the above equation, we can simply do that by subtracting $\frac{4}{g}$ from both sides of the equation

This would give:

f + $\frac{4}{g}$ - $\frac{4}{g}$ = 6 - $\frac{4}{g}$

f = 6 - $\frac{4}{g}$

Answer #2:

If the given equation was:

$\frac{f+4}{g} = 6$

To solve for f, we would still need to isolate the "f" on one side of the equation.

This can be done as follows:

$\frac{f+4}{g} = 6$ ................> multiply both sides by (g)

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f + 4 - 4 = 6g - 4

f = 6g - 4

Hope this helps :)

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3 years ago

Read 2 more answers

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horsena [70]

key words:

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What is the surface area of a 96 square foot box if it is scaled up by a factor of 10?

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3 years ago

A student earned grades of Upper AA, Upper DD, Upper AA, Upper CC, and Upper BB. Those courses had the corresponding numbers

dmitriy555 [2]

Answer:

The grade point average is 2.92

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Step-by-step explanation:

I take the grades as A,D,A,C,B not AA,DD,AA,CC,BB.

I take numbers of credit hours as 4,2,2,3,1 not as 44, 22, 22, 33, and 11.

Since quality points to letter grades are A=4; B=3; C=2; D=1; F=0, weighted mean is the sum of the qulity points times corresponding credit hours divided by the total credit hours:

$\frac{(4*4) + (1*2) + (4*2) + (2*3) + (3*1)}{12}$ ≈ 2.92

Since 2.92<3.0, the student is not in Dean's list.

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3 years ago