21 • (3k + 2m)
Step by step solution :
Step 1 :
Step 2 :
Pulling out like terms :
2.1 Pull out like factors :
9k + 6m = 3 • (3k + 2m)
Final result :
21 • (3k + 2m)
Answer:
2/5
Step-by-step explanation:
The answer is common sense.
Answer:
The length of the rectangle 'l' = 20
The width of the rectangle 'w' = 14
Step-by-step explanation:
<u>Explanation</u>:-
Let 'x' be the width
Given data the length of a rectangular patio is 8 feet less than twice its width
2x-8 = length
The area of rectangle = length X width
Given area of rectangle = 280 square feet
x(2x-8) = 280
2(x)(x-4) =280
x(x-4) =140
x^2 -4x -140=0
x^2-14x+10x-140=0
x(x-14)+10(x-14)=0
(x+10)(x-14) =0
x = -10 and x = 14
we can choose only x =14
The width of the rectangle 14
The length of the rectangle 2x-8 = 2(14)-8 = 28 -8 =20
The length of the rectangle 'l' = 20
The width of the rectangle 'w' = 14
<h2>
Answer with explanation:</h2>
Let
be the population mean lifetime of circulated $1 bills.
By considering the given information , we have :-

Since the alternative hypotheses is two tailed so the test is a two tailed test.
We assume that the lifetime of circulated $1 bills is normally distributed.
Given : Sample size : n=50 , which is greater than 30 .
It means the sample is large so we use z-test.
Sample mean : 
Standard deviation : 
Test statistic for population mean :-


The p-value= 
Since the p-value (0.0433834) is greater than the significance level (0.02) , so we do not reject the null hypothesis.
Hence, we conclude that we do not have enough evidence to support the alternative hypothesis that the average lifetime of a circulated $1 bill differs from 18 months.
Answer:
C
Step-by-step explanation: