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3 years ago

Noam solved the equation for k using the following calculations.

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

6 0

Answer:

3) He made a computation error when he added 10.35+7.6

Step-by-step explanation:

Steps to add decimals:

1)Write down the numbers, one under the other, with the decimal points lined up

2) Put in zeros so the numbers have the same length

3) Then add using column addition, remembering to put the decimal point in the answer

Applying the above steps:

line the decimals up 10.35

7.6

Putting zero to get same length

10.35

7.60

Addition:

10.35

+7.60

......................

17.95

Now we can see that, there is error when he added 10.35 + 7.6

AysviL [449]3 years ago

5 0

Answer:

He made a computation error when he added 10.35+7.6

Step-by-step explanation:

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Write an equation of a line that passes through the point (4,3) and is perpendicular to the graph of the equation y=−13x+4.

lilavasa [31]

Answer:

y = -13x + 55

Step-by-step explanation:

perpendicular formula : m1 × m2 = -1

y = -13x + 4

now we take the grafient of the equation which is 13 :

m × 13 = -1

m = -13

so now we hv a new gradient then we can find the equation use the formula y = mx + c :

m = -13 point = ( 4 , 3 )

sub them into the formula,

3 = -13 (4) + c

3 = -52 + c

3 + 52 = c

55 = c

c = 55

now we rewrite again the c and the m to become a complete equation : y = -13x + 55

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3 years ago

How many fluid ounces in 8 ounces and 5 cups?

xenn [34]

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4 years ago

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v>=2i-4tj^

guapka [62]

Given :

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .

To Find :

A. The vector position of the particle at any time t .

B. The acceleration of the particle at any time t .

Solution :

A )

Position of vector v is given by :

$d=\int\limits {v} \, dt\\\\d=\int\limits {(2i-4tj)} \, dt \\\\d=(2t)i+\dfrac{4t^2}{2}j\\\\d=(2t)i+(2t^2)j$

B )

Acceleration a is given by :

$a=\dfrac{dv}{dt}\\\\a=\dfrac{2i-4tj}{dt}\\\\a=\dfrac{2i}{dt}-\dfrac{4tj}{dt}\\\\a=0-4j\\\\a=-4j$

Hence , this is the required solution .

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3 years ago

OLEGan [10]

I would say it’s A....

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3 years ago

What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1?

MAXImum [283]

Answer:

Step-by-step explanation:

6*2-24x+1=

12+1=24x

x+1= 24/12

x+1=2

x=2-1

x=1

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3 years ago