1) Molar mass C5H12= 5*12 +1 *12=60+12=72 g/mol
2) 40g C5H12 * 1 mol C5H12/72 g C5H12 = 40/72 mol C5H12
3) C5H12 + 8O2 ------> 5CO2 + 6H2O
by reaction 1 mol 8 mol
from problem 40/72 mol x mol
x=(40/72) * 8/1=(40*8)/72=(40)/9 mol O2
4) M(O2)=2*16 g/mol =32 g/mol
5) (40)/9 mol O2 *(32 g O2/ 1 mol )=(40 * 32)/9 =142.2 g O2
The epicenter was located somewhere on a circle centered at Recording station X, with a radius of 250 km.<span>
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Answer:
the correct answer is option 'b': More than
Explanation:
The 2 situations are represented in the attached figures below
When an object is placed in air it is acted upon by force of gravity of earth which is measured as weight of the object.
While as when any object is submerged partially or completely in any fluid the fluid exerts a force in upward direction and this force is known as force of buoyancy and it's magnitude is given by Archimedes law as equal to the weight of the fluid that the body displaces, hence the effective force in the downward direction direction thus the apparent weight of the object in water decreases.
Answer:
1 : NA = 1 | 2 : N = 2 | 3 :
N = 1 | O = 5 |
O = 3 | |
Explanation:
im sorry but ion know the last one
Since Chlorine is in excess, this is a limiting reagent problem.
1) convert 11.50 g Na to g of NaCl using the balanced equation.
2) percent yield = (actual yield)/(potential yield).
.85= (actual yield)/(g from step 1)
Solve for actual yield