Answer:
0.5472 moles of H₂O are produced
0.1992 moles of C₈H₁₈ were left
Explanation:
The reaction of octane (C₈H₁₈) with oxygen (O₂) is:
C₈H₁₈ + 25/2 O₂ → 8CO₂ + 9H₂O
<em>Where 1 mole of octane reacts with 25/2 moles of oxygen to produce 8 moles of carbon dioxide and 9 moles of water</em>
For a complete reaction of 0.760moles of oxygen there are needed:
0.760 mol O₂ ₓ (1 mole C₈H₁₈ / 25/2 moles O₂) = <em>0.0608 moles of C₈H₁₈</em>
As you have 0.260 moles, the moles of octane that were left are:
0.260 mol - 0.0608 mol = <em>0.1992 moles of C₈H₁₈</em>
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Now, if 0.760 moles of O₂ react, the moles of water that are produced are:
0.760 mol O₂ ₓ (9 moles H₂O / 25/2 moles O₂) = <em>0.5472 moles of H₂O</em>
