Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
Answer:
Step-by-step explanation:
Recursive formula
tn = t_n-1 / 4
t2 = t1 / 4
t2 = 10240
t1 = 10240 / 4 = 2560
Explicit formula
tn = 10240 / 4^(n-1)
t4 = 10240 / 4^(4 - 1)
t4 = 10240 / 4^3
t4 = 10240 / 64
t4 = 160
t8 = 10240 / 4^7
t8 = 0,625
Answer:
3x + 5y = 11 -> y = -3/5x + 11/5
9x + 15y = 33 -> y = -3/5x + 11/5
Answer:
12kg
Step-by-step explanation:
because 2×2×2+4=12
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A menos que el objeto físico (en grados) de una sola partícula separe los grados 360, formará triángulos equiláteros en ese plano (esto se debe a que un número entero de ellos debe encontrarse en un vértice). Los triángulos equiláteros, los círculos y los hexágonos normales cumplen con este requisito
