L(1, -4)=(xL, yL)→xL=1, yL=-4
M(3, -2)=(xM, yM)→xM=3, yM=-2
Slope of side LM: m LM = (yM-yL) / (xM-xL)
m LM = ( -2 - (-4) ) / (3-1)
m LM = ( -2+4) / (2)
m LM = (2) / (2)
m LM = 1
The quadrilateral is the rectangle KLMN
The oposite sides are: LM with NK, and KL with NK
In a rectangle the opposite sides are parallel, and parallel lines have the same slope, then:
Slope of side LM = m LM = 1 = m NK = Slope of side NK
Slope of side NK = m NK = 1
Slope of side KL = m KL = m MN = Slope of side MN
The sides KL and LM (consecutive sides) are perpendicular (form an angle of 90°), then the product of their slopes is equal to -1:
(m KL) (m LM) = -1
Replacing m LM = 1
(m KL) (1) = -1
m KL = -1 = m MN
Answer:
Slope of side LM =1
Slope of side NK =1
Slope of side KL = -1
Slope of side MN = -1
Answer:
E. √180
Step-by-step explanation:
Using Pythagoras' theorem
a^2 + b^2 = c^2 (c = hypotenuse, a and b are legs)
a^2 = c^2 - b^2
a^2 = 18^2 - 12^2
a^2 = 324 - 144
a^2 = 180
a = √180
Answer
E. √180
Answer:
3
Step-by-step explanation:
there are 3 more markers than pencils
Given:
A car dealer acquires a used car for $14,000, with terms FOB shipping point.
Transportation cost = $100
Shipping insurance = $120
Car import duties = $970
To find:
The total inventory costs assigned to the used car.
Solution:
We know that,
Inventory costs = Value of used car + Transportation cost + Shipping insurance + Car import duties
Inventory costs = $14,000 + $100 + $120 + $970
Inventory costs = $15,190
Therefore, total inventory costs assigned to the used car is $15,190.
