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2 years ago

This is the value of a variable for an entire population. It usually cannot be found directly.

Mathematics

2 answers:

katrin [286]2 years ago

7 0

its parameter and the first two letters are pa

Paul [167]2 years ago

5 0

This is the value of a variable for an entire population. It usually cannot be found directly: the population mean. We can approx. the population mean, or specify an interval in which it is likely to lie, but we generally cannot find the value of the pop mean.

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The ratio of blue to yellow

FinnZ [79.3K]

Answer:

6 cups of blue paint

Step-by-step explanation:

The ratio can be written like this:

2:3 = x:9

9/3 = 3

3*2 = 6

x=6, so the answer is 6 cups of blue paint.

3 0

2 years ago

Rose has $426.00 in her checking account. 1⁄3 of her money will go toward bills. How

Alex Ar [27]

Answer:

$284

Step-by-step explanation:

First, find 1/3 of 426 by multiplying 1/3*426

With your answer (142), subtract that from the total in your checking account.

426-142=284

This means, After withdrawing the amount she will use to pay bills, Her left over total will be 284 dollars.

8 0

3 years ago

Read 2 more answers

Someone find area and perimeter of this shape! Thanjs

Gemiola [76]

The area would be 132cm^2 (squared)
(9x4)x2+(7+8)x4 =132

The perimeter you just add everything up so it’s 65cm
15+13+4+7+9+4+13

6 0

3 years ago

Read 2 more answers

1. What is the value of x? Show all of your work.

Colt1911 [192]

You can use the pathagorean theorm.
$a^2 + b^2 = c^2$
$a^2 + 6^2 = \sqrt{117}^2$
$a^2 + 36 = 117$
$a^2 = 117 - 36$
$a^2 = 81$
$\sqrt{a^2} = \sqrt{81}$
$a = 9$
x = 9

5 0

3 years ago

Simplify this step by step <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B-5jk%7D%7B35j%5E2k%5E2%7D%20" id="TexFormula1" tit

VikaD [51]

$\frac { -5jk }{ 35{ j }^{ 2 }{ k }^{ 2 } } \\ \\ =-\frac { 5 }{ 35 } \cdot \frac { j }{ { j }^{ 2 } } \cdot \frac { k }{ { k }^{ 2 } } \\ \\ =-\frac { 1 }{ 7 } \cdot \frac { 1 }{ j } \cdot \frac { 1 }{ k } \\ \\ =-\frac { 1 }{ 7jk }$

Remember that:

$\frac { j }{ { j }^{ 2 } } =\frac { 1 }{ j } \cdot \frac { j }{ j } =\frac { 1 }{ j } \cdot 1=\frac { 1 }{ j } \\ \\ \frac { k }{ { k }^{ 2 } } =\frac { 1 }{ k } \cdot \frac { k }{ k } =\frac { 1 }{ k } \cdot 1=\frac { 1 }{ k }$

8 0

2 years ago

Read 2 more answers