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Alinara [238K]
2 years ago
7

1 of 5

Mathematics
2 answers:
Amiraneli [1.4K]2 years ago
8 0
Since that ratio is 7 : 5 all you gotta do is add 7 +5 to get 12 the you divide 36 by 12 to get 3. Then since ur looking for the girls, u times 3 by 5 to get 15 girl students
So the answer should be 15
dolphi86 [110]2 years ago
7 0

Answer:

15 students are girls

Step-by-step explanation:

7+5=12

12x3=36

5x3=15

7x3=21

21+15=36

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Licemer1 [7]
These triangles are not congruent. They only have 2 sides and one angle in common, and that is not a congruency theorem.
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3 years ago
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ulia spends $3.25 on gas for her lawn mower. She earns $14.00 mowing her neighbor's yard. What is Julia's profit?
ipn [44]
$14.00
- _3.25_
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What is f(5)? please answer
Aneli [31]

-8

f(x) is y, in which x is the independent variable

when x = 5, y = -8

7 0
2 years ago
A rock is launched from a cannon. After 1 second, the rock is 58 feet in the air; after 2 seconds, it is 112 feet in the air. Us
max2010maxim [7]

Answer:

Step-by-step explanation: This is the quadratic function:

h(x)=ax²+bx+c

We have two points:

(1,58)

(2,112)

Now, we calculate this quadratic funtion.

we assume that h(0)=0

Therefore:

a(0)²+b(0)+c=0

c=0

(1,58)

a(1)²+b(1)=58

a+b=58  (1)

(2,112)

a(2)²+b(2)=112

4a+2b=112

2a+b=56  (1)

With the equations (1) and (2) we make a system of equations:

a+b=58

2a+b=56

we can solve this system of equations by reduction method.

-(a+b=58)

2a+b=56

---------------------

a=-2

-2(a+b=58)

2a+b=56

-------------------

      -b=-60  ⇒  b=60

The function is:

h(x)=ax²+bx+c

h(x)=-2x²+60x

Now find the height, in feet, of the rock after 10 seconds in the air.

h(10)=-2(10)²+60(10)

h(10)=-200+600=400

Answer: 400 ft.

8 0
2 years ago
Joanna runs at an average speed of 7.5km/h. She runs 15km every day. What time did
yan [13]
Avg. speed Joanna runs: 7.5km/h
how much she runs everyday: 15km

15km/7.5= 2 hours of running time everyday

She leaves at 8:30, comes back at ?
8:30+ 2:00= 10:30

Joanna arrives back at 10:30a.m.
8 0
3 years ago
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