Question

A small plane leaves an airport at a speed of 252 miles per hour. A jet leaves the airport 2 hours later traveling at 672 miles per hour. How long will the small plane be flying before the jet catches up to it

Answer 1

S=252t, j=672(t-2), when the jet catches the small plane j=s so:

672(t-2)=252t

672t-1344=252t subtract 252t from both sides

420t-1344=0  add 1344 to both sides

420t=1344  divide both sides by 420

t=3.2 hours (3:12)

Answer 2

Answer:

t=3.2 hours (3:12)

Step-by-step explanation:

i hope that helped