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babymother [125]
4 years ago
15

PLEASE HELP!!!!!!!!!!!!!!!! Find x. 2√5 3√5 6

Mathematics
1 answer:
lakkis [162]4 years ago
7 0

Answer:

6

Step-by-step explanation:

All of the triangles are similar, so the ratio of hypotenuse to short side is the same for all.

... x/4 = 9/x . . . . that ratio for smallest and largest triangles

... x^2 = 36 . . . . multiply by 4x

... x = 6 . . . . . . . take the square root

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Solve 6-7+3(-11+5)(-11+5)-5
andrew11 [14]
I think it's 112 I did it in my head might be wrong
6 0
3 years ago
Keith bought 5 new baseball trading cards to add to his collection. The next day his dog ate half of his collection. There are n
AysviL [449]

Answer:

85 cards

Step-by-step explanation:

8 0
3 years ago
Suppose the inside bottom of a box is painted with three colors: one-third of the bottom area is blue, one-sixth is red, and one
miss Akunina [59]

Answer:

The probability that the pebble will NOT land on color blue is 0.67.

Step-by-step explanation:

We attribute the box area as the probability of the events.

So the probability of landing in the Red Area is 1/6, the probability of landing in the Blue Area is 1/3 and the probability of landing in the Yellow Area is 1/2.

P(Red)=\frac{1}{6}

P(Yellow)=\frac{1}{2}

P(Blue)=\frac{1}{3}

The probability of landing in NOT Blue area is given by:

P(Not Blue)=1-P(Blue)=1-\frac{1}{3}=\frac{2}{3} =0.67

8 0
3 years ago
Which of these expressions CANNOT be simplified by combining like terms?
densk [106]
5ab^{3} +7-3a^{2} b ^{2} +a^{3}b+10 can be simplified to by adding the 7 and 10 to get a^{3}b-3a^{2} b ^{2}+ 5ab^{3} + 17.

5ab^{3}+3a^{2}b^{2}+a^{3}b -10 cannot be simplified any more by combining like terms.

By distributing the 2b into the parentheses, you can simplify the expression:
5ab^{3}+2b(3ab^{2})+a^{3}b-10\\
5ab^{3}+6ab^{3}+a^{3}b-10\\
11ab^{3}+a^{3}b-10

Here you can just add:
5a^{3}b^{3}+3a^{2}b^{2}+a^{3}b^{3}-10ab\\
6a^{3}b^{3}+3a^{2}b^{2}-10ab

Thus, the only expression that cannot simplify any more using adding like terms is the second, 5ab^{3}+3a^{2}b^{2}+a^{3}b -10.
3 0
3 years ago
Read 2 more answers
Last year 190 student attended the spring dance and the total cost was 1250. Two years ago 175 people attended and the total cos
kondor19780726 [428]
Unit cost of a ticket = Income from ticket sales / number of tickets sold:

$1250
--------------- = $6.58 per ticket
190 tickets

Again:

$1175
--------------- = $6.71
175 tickets

While ticket prices do change (usually increase) from year to year, it's unusual to see such a situation here.

Don't have any guidelines by which to determine the "fixed cost of a ticket".

If we use the cost of a ticket of 2 years ago ($6.58/ticket), then the income from the sale of 225 tickets this year would be ($6.58/ticket)(225 tickets), or $1480.50.
6 0
4 years ago
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