Answer:
Since a/2⁽ⁿ ⁺ ¹⁾b < a/2ⁿb, we cannot find a smallest positive rational number because there would always be a number smaller than that number if it were divided by half.
Step-by-step explanation:
Let a/b be the rational number in its simplest form. If we divide a/b by 2, we get another rational number a/2b. a/2b < a/b. If we divide a/2b we have a/2b ÷ 2 = a/4b = a/2²b. So, for a given rational number a/b divided by 2, n times, we have our new number c = a/2ⁿb where n ≥ 1
Since 
= a/(2^∞)b = a/b × 1/∞ = a/b × 0 = 0, the sequence converges.
Now for each successive division by 2, a/2⁽ⁿ ⁺ ¹⁾b < a/2ⁿb and
a/2⁽ⁿ ⁺ ¹⁾b/a/2ⁿb = 1/2, so the next number is always half the previous number.
So, we cannot find a smallest positive rational number because there would always be a number smaller than that number if it were divided by half.
Answer:
Step-by-step explanation:
Subset of A = { {} , {a} , {b}, {a.b} }
Your question is vague. There is not enough information. How many balls are in the box? 15 boxes would cost 109.80 thought.
Answer:
180%
Step-by-step explanation:
Set up an equation:
Variable x = percent of markup
102.56/56.98 = x/100
Cross multiply
102.56 × 100 = 56.98 × x
10,256 = 56.98x
Divide both sides by 56.98:
179.99297.... = x
Round to nearest whole number:
180 = x
Check your work:
56.98 × 180%
Convert the percentage into a decimal:
56.98 × 1.80
102.564
Round to nearest cent:
102.56
Correct!
Answer:
B. y - 35 = 2(x - 10)
Step-by-step explanation:
The height of the plant, y, after x days could be modeled by the equation
<h3>y-y0=k(x-xo) (1)
,</h3><h3>
where y0 was the initial height at 'x0'th. day, and k is the constant of proportionality.</h3><h3>
From equation (1), k could be evaluated as follows:</h3><h3>
k=(y-y0)/(x-x0) </h3><h3>
From the problem statement, we may determine k by plugging in the given values, e.g. y0= 35, x0=10, y=55, x=20.</h3><h3>
Thus,</h3><h3>
k=(55-35)/(20-10)=2</h3><h3>
Therefore, the model equation becomes</h3><h3>
y-35=2(x-10)</h3><h3>
</h3>
