Answer:
Domain: set of all real numbers
Range: 
Step-by-step explanation:
We have to find the domain and range of the function:

This is a quadratic function, shape of a "U", that's called a parabola.
The domain is the set of x values for which the function is defined.
The range is the set of y values for which the function is defined.
Normally, any parabola in the form
has domain as "all real numbers". This is the case for this problem as well, thus,
Domain = set of all real numbers
Now, for the range, we have to look at the minimum value of the function. So, the range would be y values greater than or equal to the minimum number. Lets find the minimum value of this function.
We have to find the value of x for which the minimum occurs by using the formula:

<em><u>Note: value of a is "5" and b is "10"</u></em>
Now, we plug this into the function to find the minimum value:

So, the range is set of all real numbers greater than or equal to -5.