Well this could be incredibly easy, by just saying
and
.
This is a completely valid case but nevertheless seems too easy. The requirements are probably that n and m are integers or natural numbers but since that was not specified such probable requirement ought not to be followed.
Hope this helps :)
From the given discrete distribution, we have that:

<h3>What are the mean, the variance and the standard deviation of a discrete distribution?</h3>
- The mean of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.
- The variance is given by the sum of the difference squared between each observation and the mean, divided by the number of values.
- The standard deviation is the square root of the variance.
In this problem, the distribution is:



Hence, the mean is:

The variance is:

The standard deviation is:

More can be learned about discrete distributions at brainly.com/question/24855677
Answer:
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Step-by-step explanation:
if you change 1/4 into a decimal, it turns into 0.25. So 0.35 is greater than 0.25
Answer:
A. Yes, the result is a binomial probability distribution.
Step-by-step explanation:
The experiment above depicts a binomial probability distribution because the 4 required conditions are met :
1.) The distribution is independent as the possible outcome of each trial is the same.
2.) There are two possible categories and the result of each trial is one of two outcomes : Yes or No
3.) The number of observation is fixed at sample size of 5500
4.) The probability of success and failure of each trial is the same for all trials in the sample.
Hence, we can conclude that the experiment depicts a binomial probability distribution.