The number of candies that will be <u>left over</u> after giving everyone an equal amount is equal to 23.
<u>Given the following data:</u>
- Total number of candy = 320 pieces
- Number of classmates = 27 classmates
To calculate the number of candies that will be <u>left over</u> after giving everyone an equal amount:
In this exercise, you're required to determine the number of candies Phillipe would have as <u>left over</u> after giving everyone in his class an equal amount of candies.
<h3>How to solve this word problem.</h3>
Thus, we would find the number of times 27 would divide 320 without any remainder.

- From the mixed fraction, we can deduce that the remainder is 23.
Therefore, the number of candies that will be <u>left over</u> after giving everyone an equal amount is equal to 23.
Read more on word problems here: brainly.com/question/13170908
Answer:
See explanation
Step-by-step explanation:
We want to show that:

One way is to use the basic double angle formula:


We simplify further to get:

We simplify again to get;

This finally gives:

G(x) = 2x + 2
g(a + h) - g(a) = 2(a+h) + 2 - (2(a) + 2)
g(a + h) - g(a) = 2a + 2h + 2 - 2a - 2
g(a + h) - g(a) = 2h + 2 - 2
g(a + h) - g(a) = 2h
Your final answer is a. 2h.
Answers:Part A: The value of x is 0.Part B: X can be any real number.
In Part A, you have to first evaluate 7^2. This is 49. Now, write the equation 49^x = 1. We know that if you raise any number to 0, then the answer is 1.
In Part B, you have to first evaluate 7^0, that is 1. Now, we have the equation 1^x = 1. In this case, 1 raised to any exponent is still only 1. Imagine 1^17, this would be 1 times itself 17 times or just 1.
Therefore any number will work in Part B.
Answer:
B.
The graph is stretched vertically and shifted to the left 1 unit.