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Sloan [31]
4 years ago
5

The area of a 25 inch TV screen is 300 in.². The area of a 40 inch TV screen is 768 in.². The area of the smaller screen is what

percentage of the area of the larger screen?
Mathematics
1 answer:
Rina8888 [55]4 years ago
5 0

Answer:

39.0625%

Step-by-step explanation:

The area of a 25 inc TV screen is 300in²

The area of a 40 inch TV screen is 768in²

Percentage of area of the smaller screen to larger screen is;

300/768 × 100 = 39.0625%


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X y
shutvik [7]

Step-by-step explanation:

the unit rate of y per x :

9/3 = 18/6 = 27/9 = 36/12

all the results = 3

the right answer is B) 3

7 0
3 years ago
How do you solve 1/3 of 3/4 <br> of a fraction
Trava [24]

1 1/12

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(1/3, 3/4) = 12

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(13×44)+(34×33)=?

Complete the multiplication and the equation becomes

4/12+9/12=?

The two fractions now have like denominators so you can add the numerators.

Then:

4+9/12=13/12

This fraction cannot be reduced.

The fraction

13/12

is the same as

13÷12

Convert to a mixed number using

long division for 13 ÷ 12 = 1R1, so

1312=1 1/12

Therefore:

13+34=1 11/2

5 0
3 years ago
I have bots answering some of my questions so if you get the right answer ill give brainliest and you also get some points too :
KonstantinChe [14]

Answer:

ok what's your question

4 0
3 years ago
The difference of two trinomials is x2 − 10x + 2. If one of the trinomials is 3x2 − 11x − 4, then which expression could be the
12345 [234]

Answer:

4x^2-21x-2

Step-by-step explanation:

Given that:

Difference of two trinomials is x^2 - 10x + 2

One of the two trinomials is  3x^2 - 11x - 4

To find:

The other trinomial = ?

Four options are:

2x2 - x - 2 \\2x2 + x + 6 \\4x2 + 21x + 6\\ 4x2 - 21x - 2

Solution:

Let the two trinomials be A and B.

Given A - B = x^2 - 10x + 2

B = 3x^2 - 11x - 4

We have to find the other trinomial A.

A - B = x^2 - 10x + 2

A - (3x^2 - 11x - 4) = x^2 - 10x + 2

\Rightarrow A = x^2 - 10x + 2 + (3x^2 - 11x - 4)

\Rightarrow A = 4x^2-21x-2

So, the correct answer is 4x^2-21x-2.

3 0
3 years ago
There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con
grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

\square ABCD

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD

\angle BAC = \angle  DCA

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC

and

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED

So, the congruent sides and angles of △ABE and △CDE are:

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD ---- S

\angle BAC = \angle  DCA ---- A

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED or \[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC  --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0
2 years ago
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