Question

A ball is thrown from an initial height of 2 feet with an initial upward velocity of 29 ft/s. The balls height (h) [in feet] after t seconds is given by the following
h=2+29t-16t^2
Find all the values for t for which the balls height is 14 feet

Answer 1

The ball is at a height of 14 feet after 1.17 and 0.64 seconds.

This is an example of a quadratic equation. Write out the equation with 14 in the place of the height. Then, set it equal to zero.

14 = 2 + 29t - 16t^2

0 = -16t^2 + 29t -12

Now, we can use the quadratic equation to solve.
A = -16
B = 29
C = -12

You will get the solutions of 1.17 and 0.64.