Answer:
32.92 moles of Mg
Explanation:
To convert grams to moles (Or vice versa) of any chemical compound we need to use the molar mass of the substance (That is, how many grams weighs 1 mole of the chemical).
The magnesium, Mg, has a molar mass of 24.305g/mol. That means in 800.0g of Mg you have:
800.0g * (1mol / 24.305g) =
<h3>32.92 moles of Mg</h3>
<span>4: Form An Aqueous Solution
This is the only answer that can be observed without testing gear and with the naked eye.... Hope I helped ^-^</span>
There is no Bo element, however there is a B element which is Boron
Answer:
0.4 M
Explanation:
Equilibrium occurs when the velocity of the formation of the products is equal to the velocity of the formation of the reactants. It can be described by the equilibrium constant, which is the multiplication of the concentration of the products elevated by their coefficients divided by the multiplication of the concentration of the reactants elevated by their coefficients. So, let's do an equilibrium chart for the reaction.
Because there's no O₂ in the beginning, the NO will decompose:
N₂(g) + O₂(g) ⇄ 2NO(g)
0.30 0 0.70 Initial
+x +x -2x Reacts (the stoichiometry is 1:1:2)
0.30+x x 0.70-2x Equilibrium
The equilibrium concentrations are the number of moles divided by the volume (0.250 L):
[N₂] = (0.30 + x)/0.250
[O₂] = x/0.25
[NO] = (0.70 - 2x)/0.250
K = [NO]²/([N₂]*[O₂])
K =
7.70 = (0.70-2x)²/[(0.30+x)*x]
7.70 = (0.49 - 2.80x + 4x²)/(0.30x + x²)
4x² - 2.80x + 0.49 = 2.31x + 7.70x²
3.7x² + 5.11x - 0.49 = 0
Solving in a graphical calculator (or by Bhaskara's equation), x>0 and x<0.70
x = 0.09 mol
Thus,
[O₂] = 0.09/0.250 = 0.36 M ≅ 0.4 M
Answer:
Empirical Formula N2O6Sr Strontium Nitrate
Explanation:
N=13.2% O=45.4% Sr=41.4%