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Serggg [28]
3 years ago
15

Which pair of elements will form an ionic bond?

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
4 0

I believe that the answer is A.

The combination of potassium (K) and oxygen (O2) produces K2O (potassium oxide). The balanced equation is 2K + O2 ==> K2O.

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Convert 49 lbs into grams
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<h2>Answer:</h2><h3>22226.026 g</h3><h2>Explanation:</h2>

To get an approximate result, multiply the mass value by 454.

<em>hope</em><em> </em><em>this</em><em> </em><em>help</em><em>!</em>

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3 years ago
This graph illustrates that, under conditions of constant pressure, as the temperature of liquid water increases, its volume ___
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it varies.........................
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The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when
tia_tia [17]

Answer : The cell potential for this reaction is 0.50 V

Explanation :

The given cell reactions is:

Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)

The half-cell reactions are:

Oxidation half reaction (anode):  Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction (cathode):  Pb^{2+}+2e^-\rightarrow Pb

First we have to calculate the cell potential for this reaction.

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 25^oC=273+25=298K

n = number of electrons in oxidation-reduction reaction = 2

E^o_{cell} = standard electrode potential of the cell = +0.63 V

E_{cell} = cell potential for the reaction = ?

[Zn^{2+}] = 3.5 M

[Pb^{2+}] = 2.0\times 10^{-4}M

Now put all the given values in the above equation, we get:

E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}

E_{cell}=0.50V

Therefore, the cell potential for this reaction is 0.50 V

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4 years ago
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Answer:

A. Fusion

Explanation:

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lana [24]
Equal. Good luck with other questions!
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3 years ago
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