Answer:
a = b + k + u
Step-by-step explanation:
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It’s me= and what It do baby
The linear speed of a person on this Ferris wheel is about 628.2 ft/min.
<h3>What is Linear Speed ?</h3>
As a body travels a circular path, it has both a linear speed and an angular speed. The rate it travels on that path is the linear speed, and the rate it turns around the center of that path is the angular speed. The linear speed (v) and angular speed (ω) are related by the radius (r) or v = rω .
Given that ;
Radius = r = 50 ft
Frequency = f = 2 rev/min
The angular speed is the product of the angular displacement for one complete turn, namely 2π radians per revolution, and the frequency (f). That is, the angular speed is equal to ω = 2πf. Substituting this into the formula for linear speed (v), we get:
v = r (2πf)
= (50 ft) ( 2π / rev) ( 2 rev/min)
= 200π ft/min
≈ 628.2 ft/min
The linear speed of a person on this Ferris wheel is about 628.2 ft/min.
Learn more about linear speed here ;
brainly.com/question/14413779
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Answer:
The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,
4.2 ft
Step-by-step explanation:
The equation for the volume of a pyramid of base area B and height h is
V = (1/3)·B·h. Here, V = 432 ft³, B = (12 ft)² and h (height of the pyramid) is unknown. First we find the height of this pyramid, and then the slant height.
V = 432 ft³ = (144 ft²)·h, so h = (432 ft³) / (144 ft²) = 3 ft.
Now to find the slant height of this pyramid: That height is the length of the hypotenuse of a right triangle whose base length is half of 12 ft, that is, the base length is 6 ft, and the height is 3 ft (as found above).
Then hyp² = (3 ft)(6 ft) = 18 ft², and the hyp (which is also the desired slant height) is hyp = √18, or √9√2, or 3√2 ft.
The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,
4.2 ft
