All categories

4 years ago

Which is closest to the distance between A and B on the number

Mathematics

1 answer:

nata0808 [166]4 years ago

7 0

Answer:

C) 13

Step-by-step explanation:

A on the number line is about -5 and B is 8. Act as if there wasn't a negative sign in front of the 5. Add the two numbers together the get the distance.

You might be interested in

Please help me on this will give you brainliest

klemol [59]

Answer:

9/10 > 7/8

Step-by-step explanation:

The least common denominator (LCD) is: 40.

Rewriting as equivalent fractions with the LCD:

9/10 7/8

36/40 35/40

Comparing the numerators of the equivalent fractions we have:

9/10 7/8

36/40 > 35/40

Therefore, comparison shows:

9/10 > 7/8

8 0

3 years ago

Can anybody correct me on this right away if you got any time? click/tap in here for the image

Mandarinka [93]

Answer:

Yep, they all match:

1. Correct

2. Correct

3. Correct

4. Correct

Step-by-step explanation:

√2 • √3 • √3 = 4.242640687119285‬

3√2 = 4.242640687119285‬

√2 • √3 • √-3 = 4.24264069i

3i√2 = 4.24264069i

√-2 • √-3 • √-3 = -4.24264069i

-3√2 = -4.24264069i

√2 • √-3 • √-3 = -4.24264069i

-3i√2 = -4.24264069i

8 0

4 years ago

What is the y-intercept of the line connecting (–6,3) and (0,0)?<br><br> option 4. b = -6

solmaris [256]

The y intercept is 0. =)

5 0

3 years ago

Read 2 more answers

The internal auditing staff of a local manufacturing company performs a sample audit each quarter to estimate the proportion of

kondaur [170]

Ouch, kinda crippled w/o answer choices.

But with my calculating, i've made it out to be <span>92.07 %

Please do respond & rate based on my accuracy.
-Feeling confident-
</span>

7 0

4 years ago

A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec

VMariaS [17]

Answer:

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=19.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=9-1=8$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that $t_{\alpha/2}=$

Now we have everything in order to replace into formula (1):

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

5 0

4 years ago