Area=1/2bh
h=altitude
b=legnth of base
b is 3 times h
b=3h
divide by 3
b/3=h
area=1/2bh
subsitute b/3 for h
54=1/2(b)(b/3)
multiply bothsides by 2/1
108=b(b/3)
108=(b^2)/3
multipy both sides by 3
324=b^2
square root boh sides
18=b
legnth of base=18
Answer:
-24.8 m/s
Step-by-step explanation:
Given:
y₀ = 60 m
y = 40 m
v₀ = 15 m/s
a = -9.8 m/s²
Find: v
There are three constant acceleration equations we can use:
y = y₀ + v₀ t + ½ at²
v = at + v₀
v² = v₀² + 2a(y − y₀)
We aren't given the time, so we need to use the third equation, which is independent of time:
v² = v₀² + 2a(y − y₀)
Plug in the values:
v² = (15 m/s)² + 2(-9.8 m/s²) (40 m − 60 m)
v² = 617 m²/s²
v ≈ ±24.8 m/s
Since the coin is on the way down, the velocity is negative. So v = -24.8 m/s.
Answer:
75
225÷3=75
Step-by-step explanation:
hshshshshs
Answer:
7.3≤x<7.4
Step-by-step explanation:
<span>the area of the circle :
r = 9\2
so :
S= r</span>² * Pi = (9\2)² * 3.14 = 63.58 cm²
