All categories

3 years ago

40,000 is 10 times as much as

Mathematics

1 answer:

Dimas [21]3 years ago

3 0

40,000 is 10 times as much as 4,000

You might be interested in

If y varies directly as x and y=15 when x =5, what is the value of y when x = 15?

yulyashka [42]

Y=5 just flip the question sort of

7 0

3 years ago

If v varies directly as w, and v=24 when w= 8, find the equation that relates v and w

Zigmanuir [339]

Answer:

v=3w

Step-by-step explanation:

v∝w

v=kw

24=8k

k=24/8 = 3

equation connecting v and w is

v=3w

5 0

3 years ago

A recent survey found that 7575% of all adults over 50 wear glasses for driving. In a random sample of 4040 adults over 50, wh

malfutka [58]

Answer:

Mean = 30

standard Deviation = 2.74

Step-by-step explanation:

Formula

mean = np

Standard Deviation = $\sqrt{npq}$

from the question = 40

P = 75% or 0.75

q = 1 - p = 1 - 75% or 1 - 0.75

To find mean

mean = 40 x 0.75

= 30

For Standard Deviation (SD)

Standard Deviation = $\sqrt{npq}$

= $\sqrt{40 X 0.75 X 0.25$

= $\sqrt{7.5}$

:. Standard Deviation = 2.74

5 0

3 years ago

Which of the following facts, if true, would allow you to prove that lines l and m are parallel? NEED HELP

Damm [24]

Two parallel lines A and B are crossed by another line as shown in the attached figure. Angle 2 and 3 are equal, because they are opposite angles, while angle 3 and 7 are also equal, because they are corresponding angles, thus it is deduced that

angle 2 = angle 3

angle 3 = angle 7

So angle 2 = angle 7

Hence fourth option is right.

8 0

3 years ago

Find cos(2*ABC) 100POINTS

juin [17]

Answer:

$-\dfrac{7}{25}$

Step-by-step explanation:

Trigonometric Identities

$\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B$

Trigonometric ratios

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos(\angle ABC)=\dfrac{3}{5}$

$\sin(\angle ABC)=\dfrac{4}{5}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}$

7 0

2 years ago

Read 2 more answers