two consecutive integers: x,x+1
x+(x+1) = 9(x) - 5(x+1)
2x+1 = 9x-5x-5
2x+1 = 4x-5
subtract 2x from each side
1 = 2x-5
add 5 to each side
6 = 2x
divide by 2
x=3
the integers are 3 and 4
Answer:
A) 
General Formulas and Concepts:
<u>Calculus</u>
Discontinuities
- Removable (Hole)
- Jump
- Infinite (Asymptote)
Integration
- Integrals
- Definite Integrals
- Integration Constant C
- Improper Integrals
Step-by-step explanation:
Let's define our answer choices:
A) 
B) 
C) 
D) None of these
We can see that we would have a infinite discontinuity if x = 2/3, as it would make the denominator 0 and we cannot divide by 0. Therefore, any interval that includes the value 2/3 would have to be rewritten and evaluated as an improper integral.
Of all the answer choices, we can see that A's bounds of integration (interval) includes x = 2/3.
∴ our answer is A.
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Book: College Calculus 10e
Answer:
Step-by-step explanation:
nah man. i dont get it either
X= a number
29 - 2x= 21
subtract 29 from both sides
-2x= -8
divide both sides by -2
x= 4
CHECK:
29 - 2x= 21
29 - 2(4)= 21
29 - 8= 21
21= 21
ANSWER: The number is 4.
Hope this helps! :)
Answer:
38.2 %
Step-by-step explanation:
120/100 = 1.2 (average time)
(1.2 - 1.5)/1 = -.3
z table value for "-.3" is .3821