A
Step-by-step explanation:First, subtract
2
π
r
2
from each side of the equation to isolate the
h
term:
S
−
2
π
r
2
=
2
π
r
h
+
2
π
r
2
−
2
π
r
2
S
−
2
π
r
2
=
2
π
r
h
+
0
S
−
2
π
r
2
=
2
π
r
h
Now, divide each side of the equation by
2
π
r
to solve for
h
:
S
−
2
π
r
2
2
π
r
=
2
π
r
h
2
π
r
S
−
2
π
r
2
2
π
r
=
2
π
r
h
2
π
r
S
−
2
π
r
2
2
π
r
=
h
h
=
S
−
2
π
r
2
2
π
r
Or
h
=
S
2
π
r
−
2
π
r
2
2
π
r
h
=
S
2
π
r
−
2
π
r
2
2
π
r
h
=
S
2
π
r
−
r
2
r
h
=
S
2
π
r
−
r
X=12 because 3 times 12 equals 36. if you divide by 3 on both sides you would be left with that
Answer:its joe mama
Step-by-step explanation:
Hahahhahahahahahahah
D = sq.root of((x2 - x1)^2 + (y2 - y1)^2)
sq.root of 13 = sq.root of((x - (-2))^2 + (1 - 3)^2)
= sq.root of((x + 2)^2 + (-2)^2)
= sq.root of (x^2 + 4x + 4 + 4)
= sq.root of (x^2 + 4x + 8)
Now if we square both sides:
x^2 + 4x + 8 = 13
x^2 + 4x - 5 = 0
(x + 5)(x - 1) = 0
x = -5 or x = 1
