Question

Given that a=43 ,b=82 , and c=28, solve triangle abc. round to the nearest tenth.

Answer 1

Answer:

C= 55°, b= 33.8 units length , a= 23.3 units length

Step-by-step explanation:

The question is incomplete. The complete data is: a=43°, b=82° and c=28 units length

We know that the addition of the angles of a triangle is 180°, then: c = 180° - 43° - 82° = 55°

From law of sines:

sin(a)/a = sin(c)/c

sin(a)*c/sin(c) = a

sin(43°)*28/sin(55) = a

a = 23.3  units length

sin(b)/b = sin(c)/c

sin(b)*c/sin(c) = b

sin(82°)*28/sin(55) = b

b = 33.8  units length

Answer 2

Answer:

NO triangle exists.

Step-by-step explanation:

Given that the sides of the triangle are  a=43 ,b=82 , and c=28

To solve for unknown angles of the triangle

PLease refresh the triangle rule of inequality that the sum of any two sides is always greater than the third side

Before solving the triangle, let us check whether this is true.

a+b >c

b+c>a

But a+c is not greater than b.

Hence there cannot be any real triangle with these sides given.

Answer is no triangle exists.