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ozzi
2 years ago
10

State if the triangles in each pair are similar. If so, state how you know they are similar.

Mathematics
1 answer:
Zarrin [17]2 years ago
6 0

Answer:

<em>A) similar; SAS similarity.</em>

Step-by-step explanation:

<u>SAS Triangle Similarity</u>

The SAS criterion for triangle similarity states that if two sides of one triangle are proportional to two sides of another triangle and their included angles are congruent, then the triangles are similar.

We are given two triangles BCD and JKL. Sides DB and JL have a ratio of 90/20 = 4.5

Sides JK and BC have a ratio of 81/18 = 4.5

Since both sides are proportional and their included angle of 43° are congruent, then both triangles are similar, SAS similarity.

A) similar; SAS similarity.

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Find the mean of the data summarized in the given frequency distribution . Compare the computed mean to the actual mean of 57.6
AlexFokin [52]

The mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F is lesser than the actual mean of 57.6° F.

<h3>What is the mean of a distribution?</h3>

The mean of the distribution can be defined as the average value of the distribution, It can be expressed as the total sum of all the observed values divided by the frequency of the distribution.

From the parameters given:

Low-temperature             Frequency

40 - 44                                    2

45 - 49                                    5

50 - 54                                    9

55 - 59                                    6

60 - 64                                    3

The first thing to do is to determine the class midpoint. The class midpoint is the sum of the class interval divided by 2.

The class midpoint of 40 - 44 is \mathbf{\dfrac{40 + 44}{2} = 42}

The class midpoint of 45 - 49 is \mathbf{\dfrac{45 + 49}{2} = 47}

The class midpoint of 50 - 54 is \mathbf{\dfrac{50 + 54}{2} = 52}

The class midpoint of 55 - 59 is \mathbf{\dfrac{55 + 59}{2} = 57}

The class midpoint of 60 - 64 is \mathbf{\dfrac{60 + 64}{2} = 62}

Now, the table can be represented as:

Low-temperature             Frequency          x  

40 - 44                                    2                   42

45 - 49                                    5                   47

50 - 54                                    9                   52

55 - 59                                    6                   57

60 - 64                                    3                   62

The mean can now be determined as follows:

\mathbf{\bar x = \dfrac{\sum fx}{\sum f }}

\mathbf{\bar x = \dfrac{(2 \times 42)+ (5 \times 47) + ( 9\times 52) +(6\times 57) + (3 \times 62)}{2 + 5 + 9 + 6 + 3 }}

\mathbf{\bar x = \dfrac{1315}{25}}

\mathbf{\bar x = 52.6}

Therefore, we can conclude that the mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F. is lesser than the actual mean of 57.6° F

Learn more about the mean of frequency distribution here:

brainly.com/question/12269435

3 0
2 years ago
Jeremy wants to know the density of a rock in grams per cubic centimeter. The rock has a mass of 1.08 kilograms and a volume of
baherus [9]

Let's convert the units first.

1.08 kg * (1000 g)/(1 kg) = 1008 g

density = mass/volume

density = 1008 g / 400 cm^3

density = 2.52 g/cm^3

Answer: 2.52 g/cm^3

6 0
2 years ago
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What is 904 divided by 16. Must show answer
bulgar [2K]

Answer:

56.5

Step-by-step explanation:

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9(k-2)=-6 what is K the oz
Fynjy0 [20]

Answer:k=0.67

Step-by-step explanation:

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Tyler and Bethany have a 240 feet of fencing with which to build a garden Tyler wants the garden to be in the shape of a square
Andrej [43]
If the garden were in the shape of a square, all of its sides would be of equal length. so if you divide 240 by 4 sides, each one would be 60 feet. Then, to find the square garden's area, you multiply 60 x 60 = 360 feet².

If the garden was 50 by 70, you would multiply the two values together to find the area, which is 350 feet².

Because 360 > 350 , Tyler's design would yield the maximum area for a garden
Hope this helps :)
4 0
3 years ago
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