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natali 33 [55]
3 years ago
10

The estimated probability of a bowler getting a strike during a particular frame is 79%. If several simulations of the bowler bo

wling two frames were performed, in what percentage of the simulations would the bowler be most likely to get a strike in each of the two frames?
Mathematics
2 answers:
lianna [129]3 years ago
5 0
61...............................
Lostsunrise [7]3 years ago
3 0

Answer:

61 (Apex)

Step-by-step explanation:

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One of the roots of the equation 5x2−36x+t=0 is five times as big as the other root. Find the value of t.
Bas_tet [7]

Answer:

  t = 36

Step-by-step explanation:

If one of the roots is "a", the equation can be factored as ...

  (5x -a)(x -a) = 0

  5x^2 -6ax +a^2 = 0

Comparing terms to the given equation, we see that ...

  -6ax = -36x

  a = 6 . . . . . . . . divide by -6

Then ...

  a^2 = t

  36 = t . . . . . . . substitute 6 for a

_____

The roots are 6 and 6/5.

4 0
3 years ago
Please please help!!!!!!
RideAnS [48]

Answer:

input = 5

Step-by-step explanation:

y = -2x - 6

When y = -16

-16 = -2x - 6

divide by -2 on both sides,

8 = x + 3

x = 8 - 3 = 5

6 0
2 years ago
Joe spends $8 on lunch and 6.50 on dry cleaning.He also buys 2 shirts that cost the same amount. Joe spends a total of $52.What
emmainna [20.7K]
52-8=44
44-6.50=37.50
37.50/2=18.75
18.75 per shirt
4 0
3 years ago
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What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
3 years ago
(Pre calc) I only need to do part A i would love to have some help I will make it 120 Points
Elanso [62]

Answer:

ew

Step-by-step explanation:

8 0
3 years ago
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