Answer:
   t = 36
Step-by-step explanation:
If one of the roots is "a", the equation can be factored as ...
   (5x -a)(x -a) = 0
   5x^2 -6ax +a^2 = 0
Comparing terms to the given equation, we see that ...
   -6ax = -36x
   a = 6 . . . . . . . . divide by -6
Then ...
   a^2 = t
   36 = t . . . . . . . substitute 6 for a
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The roots are 6 and 6/5.
 
        
             
        
        
        
Answer:
input = 5
Step-by-step explanation:
y = -2x - 6
When y = -16
-16 = -2x - 6
divide by -2 on both sides,
8 = x + 3
x = 8 - 3 = 5
 
        
             
        
        
        
Answer:
 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.
 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.
Step-by-step explanation:
Given the function

As the highest power of the x-variable is 3 with the leading coefficients of 1.
- So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.
solving to get the zeros

 ∵
              ∵  
as

so
 
     
Using the zero factor principle
if  


Therefore, the zeros of the function are:

 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.
 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.
Therefore, the last option is true.