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cluponka [151]
4 years ago
12

Choose the graph. Find the angle of theta if secθ=-13/5 and tanθ is negative.

Mathematics
1 answer:
solmaris [256]4 years ago
3 0

Answer:-12/5

Step-by-step explanation:

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AB is tangent to O. If AO=12 and BC=25 what is AB ? The diagram is not to scale.
Marat540 [252]
The answer is A


AO = 12

BC= 25+ 12= 37
you can get help from Pythagoras theorem
{37}^{2} =  {12}^{2}  +  {x}^{2}  \\  -  {x}^{2}  =  {12}^{2}    -   {37}^{2}  \\  -  {x}^{2}  = 144 - 1369 = -  1225 \\1225 =  {x}^{2}
x =  \sqrt{1225}  = 35


good luck
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3 years ago
If (cos)x= 1/2 what is sin(x) and tan(x)? Explain your steps in complete sentences.
Natasha_Volkova [10]
The correct answers are:
1) sin(x) = \frac{ \sqrt{3} }{2}
2) tan(x) = \sqrt{3}

Explanation:
Given:
cos(x) =  \frac{1}{2}

Step 1:
Since, according to the Trigonometric identity:
sin^2(x) + cos^2(x) = 1 -- (1)

Step 2:
Plug in the value of cos(x) in equation (1):
sin^2(x) + ( \frac{1}{2} )^2 = 1 \\ sin^2(x) + \frac{1}{4} = 1 \\ sin^2(x)  =  \frac{3}{4}

Step 3:
Take square-root on both sides:
\sqrt{sin^2(x)} =  \sqrt{\frac{3}{4}}

sin(x) = \frac{ \sqrt{3} }{2}

Now to find the tan(x), we would use the following formula:

tan(x) = \frac{sin(x)}{cos(x)} --- (2)

Plug in the values of sin(x) and cos(x) in equation (2):
tan(x) = \frac{ \frac{ \sqrt{3} }{2} }{ \frac{1}{2} }

Hence tan(x) = \sqrt{3}
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