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Harrizon [31]
3 years ago
10

Column 1 would be on the x-axis, and Column 2 would be

Physics
1 answer:
JulsSmile [24]3 years ago
3 0
The first answer column one is time and column two is velocity
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Imagine that an uncharged pith ball is brought into the electrostatic field of a charged rod. The side of the pith ball closest
nataly862011 [7]

As per the question the uncharged pith ball is taken towards the electrostatic field of a charged rod.

It is told that the side of the pith ball is closest to the negatively charged end of the rod .

The pith ball was initially neutral.The electrons in the atom were oriented in their respective orbits.

Whenever it is taken towards the negative end of the rod,the electrons present in the ball will not stick to their orbit .Basically the closest electrons will suffer electrostatic repulsive force and will come out their orbits.They will move towards the other end of the pith ball.Hence the closest side of the pith ball will acquire  positive charges and other side will be negative.

The bound charges nearest to the charged rod is called induced positive charges and bound negative  charges present at the other end are called free bound charges.The induced charges and free charges are equal in amount.Hence the pith ball is neutral.

Hence from above we see that only option B  is right.

5 0
3 years ago
Read 2 more answers
HELP PLEASE GIVING 30 POINTS AND BRAINLIEST DUE VERY SOON!!
olga55 [171]

Answer:

3 is your anwser

Explanation:

5 0
3 years ago
What is buoyant force​
Xelga [282]

Answer:

When an object is immersed in water. it is pulled downwards due to gravitational pull of earth. Water exerts upward force on the object. This makes object rise up. This upward force is called buoyancy or upthrust.

7 0
2 years ago
I will mark you as brainliest. if you answer my question
Shalnov [3]

First, let's list everything we have...

a = 1.83 m/s^2

F = 1870 N (converted from kN to N)

vi = 0 m/s (it says started from rest, therefore velocity starts at 0)

t = 16 s

1). "Force acting on the car" is a bit ambiguous because there are many forces. But I'm going to assume that they are looking for just a basic implementation of force equation:

F=ma

where:

F = force

m = mass

a = acceleration

2). I recommend memorizing your equations of motion, because once you know them this part is also just as easy:

v_f=v_i+at

where:

vf = final velocity

vi = initial velocity

a = acceleration

t = time

5 0
3 years ago
Please help!<br>Much appreciated!​
raketka [301]

Answer:

Rp = 3.04×10² Ω.

Explanation:

From the question given:

1/Rp = 1/4.5×10² Ω + 1/ 9.4×10² Ω

Rp =?

We can obtain the value of Rp as follow:

1/Rp = 1/4.5×10² + 1/ 9.4×10²

Find the least common multiple (lcm) of 4.5×10² and 9.4×10².

The result is 4.5×10² × 9.4×10²

Next, divide the result of the lcm by each denominator and multiply the result obtained with the numerator as shown below:

1/Rp = (9.4×10² + 4.5×10²) /(4.5×10²) (9.4×10²)

1/Rp = 13.9×10²/4.23×10⁵

Cross multiply

Rp × 13.9×10² = 4.23×10⁵

Divide both side by 13.9×10²

Rp = 4.23×10⁵ / 13.9×10²

Rp = 3.04×10² Ω.

6 0
4 years ago
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