I will mark you as brainliest. if you answer my question
1 answer:
First, let's list everything we have...
a = 1.83 m/s^2
F = 1870 N (converted from kN to N)
vi = 0 m/s (it says started from rest, therefore velocity starts at 0)
t = 16 s
1). "Force acting on the car" is a bit ambiguous because there are many forces. But I'm going to assume that they are looking for just a basic implementation of force equation:
where:
F = force
m = mass
a = acceleration
2). I recommend memorizing your equations of motion, because once you know them this part is also just as easy:
where:
vf = final velocity
vi = initial velocity
a = acceleration
t = time
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Answer:
a. t = 1.43 s
b. d = 7.88 m
Explanation:
a. The time of flight can be found using the following equation:
Where:
: is the final height = -10 m
: is the initial height = 0
: is the initial speed in the vertical direction = 0
g: is the acceleration due to gravity = 9.81 m/s²
By solving the above equation for "t" we have:
Hence, the ball will hit the ground in 1.43 s.
b. The distance in the horizontal direction can be found as follows:
Where:
x₀: is the initial position in the horizontal direction = 0
a: is the acceleration in the horizontal direction = 0 (it is moving at constant speed)
Therefore, the ball will travel 7.88 m before it hits the ground.
I hope it helps you!