First, let's list everything we have...
a = 1.83 m/s^2
F = 1870 N (converted from kN to N)
vi = 0 m/s (it says started from rest, therefore velocity starts at 0)
t = 16 s
1). "Force acting on the car" is a bit ambiguous because there are many forces. But I'm going to assume that they are looking for just a basic implementation of force equation:
where:
F = force
m = mass
a = acceleration
2). I recommend memorizing your equations of motion, because once you know them this part is also just as easy:
where:
vf = final velocity
vi = initial velocity
a = acceleration
t = time
Answer:
Velocity of a proton,
Explanation:
It is given that,
Potential difference,
Let v is the velocity of a proton that has been accelerated by a potential difference of 15 kV.
Using the conservation of energy as :
q is the charge of proton
m is the mass of proton
or
So, the velocity of a proton is . Hence, this is the required solution.
Answer:
The component form will be;
In the x-axis = 121.73 due west
In the y-axis = 690.35 due south
Explanation:
An image of the calculation has been attached
