First, let's list everything we have...
a = 1.83 m/s^2
F = 1870 N (converted from kN to N)
vi = 0 m/s (it says started from rest, therefore velocity starts at 0)
t = 16 s
1). "Force acting on the car" is a bit ambiguous because there are many forces. But I'm going to assume that they are looking for just a basic implementation of force equation:
where:
F = force
m = mass
a = acceleration
2). I recommend memorizing your equations of motion, because once you know them this part is also just as easy:
where:
vf = final velocity
vi = initial velocity
a = acceleration
t = time
Answer:
r = 1.16 m
Explanation:
It is given that,
Magnetic field,
Velocity of proton,
We need to find the radius (in m) of the circular path the particle will follow when it is travelling within the magnetic field. The radius followed by the proton is given by :
m is mass of proton,
So,
So, the radius of circular path is 1.16 m.
Answer:
f = -60 cm, this means tha the focal point is on the same side as the side where the object is located.
Explanation:
let u be the distance from the lens to the object and u = -35 cm, v be the distance from the lens to the image and m is the magnification and m = -v/u and f is the focal point.
