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An equation of the circle that will pass through the four (4) vertices of the square is (x + 2)² + y² = 2².
<h3>How to find the equation of this circle?</h3>
Mathematically, the general form of the equation of a circle is given by;
(x - h)² + (y - k)² = r²
Where:
- h and k represents the coordinates at the center.
- r is the radius of a circle.
<u>Note:</u> The center of a circle lies on the midpoint of the diagonal of a square, which is formed by joining its endpoints (opposite).
Midpoint on x-coordinate is given by:
Midpoint = (-2 - 2)/2
Midpoint = -4/2 = -2.
Midpoint on y-coordinate is given by:
Midpoint = (-2 + 2)/2
Midpoint = 0/2 = 0.
Thus, the center (h, k) = (-2, 0).
For the radius, we have:
r = √(-2)² + 0²
r = √4 = 2.
Substituting the parameters into the general equation, we have;
(x - (-2))² + (y - 0)² = 2²
(x + 2)² + y² = 2²
Read more on circle here: brainly.com/question/1615837
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D. 117
4(5)^2+2(5)+7
4(25)+(10)+7
100+10+7= 117
Answer:
5
Step-by-step explanation:
Plug in the numeric values
4 for m, -9 for n, -2 for p, and 12 for q.
add them together.
4 + -9 = -5
-5 + -2 = -7
-7 + 12 = 5
Your answer is 5
hope this helps
The answer would be < because that’s greater than