For this case we must resolve the following inequality:
Adding 7 to both sides of the inequality:
Different signs are subtracted and the major sign is placed.
Thus, the solution is given by all the values of "x" less than -5.
The solution set is: (-∞, - 5)
Answer:
See attached image
The 2nd choice is appropriate.
Answer:
Step-by-step explanation:
I like to use a graphing calculator for finding the zeros of higher order polynomials. The attachment shows them to be at x = -3, -1, +2.
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The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...
x² +x -6
which factors as (x -2)(x +3), so telling you the remaining roots are -3 and +2.
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For any odd-degree polynomial with a positive leading coefficient, the sign of the function will match the sign of x when the magnitude of x gets large. Thus as x approaches negative infinity, so does f(x).
