First, find the number of females in the class.
Then, just write the ratio.
Do all quadrilaterals have all right angles
2 answers:
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Answer:
Step-by-step explanation:
Given:
Required:
f(g(x))=?
Solution:
let f(g(x))=f(X), where X=g(x)
so
put X=, we get
Answer is 54^2.
since there are triangles in this one, it is easier to do this. all you have to do is make boxes in and since there are angles, outside the lines. like this picture.
the orange is 1
red and dotted is 2
blue is 3
purple is 4(a regular box which should be easy to count.
all you have to do is add up all the boxes within the boundaries.
boundary 1: 12
boundary 2: 18
boundary 3: 6
boundary 4: 36
now when the boundary has a triangle in it (1, 2, & 3) divide the number you got in half or 2.
boundary 1: 6
boundary 2: 9
boundary 3: 3
the ractangle box doesn't not get divided.
boundary 1: 6
boundary 2: 9
boundary 3: 3
boundary 4: 36
add all the numbers you got now for each boundary and that would be your area squared.
6+9+3+36=54^2
so your final answer is 54^2.
i hope this helps you.
since there are triangles in this one, it is easier to do this. all you have to do is make boxes in and since there are angles, outside the lines. like this picture.
the orange is 1
red and dotted is 2
blue is 3
purple is 4(a regular box which should be easy to count.
all you have to do is add up all the boxes within the boundaries.
boundary 1: 12
boundary 2: 18
boundary 3: 6
boundary 4: 36
now when the boundary has a triangle in it (1, 2, & 3) divide the number you got in half or 2.
boundary 1: 6
boundary 2: 9
boundary 3: 3
the ractangle box doesn't not get divided.
boundary 1: 6
boundary 2: 9
boundary 3: 3
boundary 4: 36
add all the numbers you got now for each boundary and that would be your area squared.
6+9+3+36=54^2
so your final answer is 54^2.
i hope this helps you.