Answer: Water H2O
Explanation:
In cellular respiration process NAD+ is a most versatile electron acceptor and functions in several of the redox steps during break down of glucose.
Each NADH molecules formed during respiration represents stored energy that can be tapped to make ATP when the electrons complete their ''fall''down an energy gradient from NADH to oxygen.
Electrons removed from glucose are shuttle by NADH to the ''top'', higher-energy end of the electron transport chain. At the ''bottom'' lower energy end, O2 captures these electrons along with H+ forming water.
Therefore Hydrogen removed from NADH in the ETC is captured by O2 to form water
2H + 1/2O2 ------> H20
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Answer is: b) decomposition.
Synthesis is reaction of two or more substances combining to make a more complex substance.
Decomposition is reaction where one substance is broken down into two or more simpler substances.
For example, balanced chemical reactio:
CaCO₃(s) → CaO(s) + CO₂(g).
Chemical decomposition is the separation of a single chemical compound (in this example calcium carbonate) into its two or more simpler compounds (in this example calcium oxide and carbon dioxide).
Combustion is reaction with oxygen.
Single Displacement is reaction where neutral element metal or nonmetal become an ion as it replaces another ion in a compound.
Double displacement reactions (more reactive metals displace metals with lower reactivity).
Answer: Option (a) is the correct answer.
Explanation:
The given data is as follows.
= 4.19 
= 1.9
Heat of vaporization (
) at 1 atm and 
is 2259 kJ/kg
= 0
Therefore, calculate the enthalpy of water vapor at 1 atm and as follows.
= +
= 0 + 2259 kJ/kg
= 2259 kJ/kg
As the desired temperature is given 
and effect of pressure is not considered. Hence, enthalpy of liquid water at 10 bar and is calculated as follows.
= 
= 334.781 kJ/kg
Hence, enthalpy of water vapor at 10 bar and is calculated as follows.
= 
= 2410.81 kJ/kg
Therefore, calculate the latent heat of vaporization at 10 bar and as follows.
= 
= 2410.81 kJ/kg - 334.781 kJ/kg
= 2076.029 kJ/kg
or, = 2076 kJ/kg
Thus, we can conclude that at 10 bar and latent heat of vaporization is 2076 kJ/kg.
