Mass of KNO₃ : = 40.643 g
<h3>Further explanation</h3>
Given
28.5 g of K₃PO₄
Required
Mass of KNO₃
Solution
Reaction(Balanced equation) :
2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃
mol K₃PO₄(MW=212,27 g/mol) :
= mass : MW
= 28.5 : 212,27 g/mol
= 0.134
Mol ratio of K₃PO₄ : KNO₃ = 2 : 6, so mol KNO₃ :
= 6/2 x mol K₃PO₄
= 6/2 x 0.134
= 0.402
Mass of KNO₃ :
= mol x MW KNO₃
= 0.402 x 101,1032 g/mol
= 40.643 g
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Answer:
The molecular formula of the given compound is C6H12O6, which is also called Glucose.
Explanation:
The molar mass of glucose is 180.18.
Actual yield and theoretical yield are usually different.
the percentage yield of product = actual yield / theoretical yield x 100%
the theoretical yield is 53.8 g
and percentage yield - 73.6 %
from the theoretical yield only 73.6 % of that amount is in the actual yield
therefore actual yield is 73.6 % of 53.8 g
actual yield - 53.8 x 73.6% = 39.6 g
actual yield is 39.6 g
