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Whitepunk [10]
4 years ago
13

7g – 2g + g + 3g = 18

Mathematics
2 answers:
In-s [12.5K]4 years ago
5 0
G = 2

Hope This Is Sufficient !!
notsponge [240]4 years ago
4 0
7g - 2g + g +3g = 18
9g=18
g=2 
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3 years ago
The number of chocolate chips in a popular brand of cookie is normally distributed with a mean of 22 chocolate chips per cookie
MA_775_DIABLO [31]

Answer:

The cutoff numbers for the number of chocolate chips in acceptable cookies are 16.242 and 27.758

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 22, \sigma = 3.5

Middle 90%

Between the 50 - (90/2) = 5th percentile to the 50 + (90/2) = 95th percentile.

5th percentile:

X when Z has a pvalue of 0.05. So X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 22}{3.5}

X - 22 = -1.645*3.5

X = 16.242

95th percentile:

X when Z has a pvalue of 0.95. So X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 22}{3.5}

X - 22 = 1.645*3.5

X = 27.758

The cutoff numbers for the number of chocolate chips in acceptable cookies are 16.242 and 27.758

3 0
3 years ago
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3 years ago
Could someone please help
ololo11 [35]
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5(1/2)+5(1/2)= 10(2/2), which equals to 11.

5(1/2) is also 5.5, since 1/2 is 50/100.

5.5 + 5.5 = 11


8 0
4 years ago
Read 2 more answers
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maxonik [38]

Answer:

76%

Step-by-step explanation:

84/350 = 24%

That means, 24% of the songs were free and 76% were paid.

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