Help with question 16 ASAP

Hey need some help with this problem, its trigonometry with right triangles using SohCahToa if you can give me a hand it would b

Firlakuza [10]

For the given triangle, the value of x equals 30.9892 units.

Step-by-step explanation:

Step 1:

In the triangle, the angle is 40°, the opposite side has a length of 26 units, the adjacent side has a length of x units while the hypotenuse is not given.

To determine the value of x, we determine the value of the tan of the given triangle.

To calculate the tan of angle A we divide the opposite side's length by the the adjacent side's length.

$tan A = \frac{oppositeside}{adjacent side}.$

Step 2:

The length of the opposite side = 26 units.

The length of the adjacent side = x units.

$tan A = \frac{oppositeside}{adjacent side}, tan 40 = 0.8390, tan A = \frac{26}{x} .$

$0.8390 = \frac{26}{x} , x = \frac{26}{0.8390} = 30.9892.$

So x measures 30.9892 units.

6 0

3 years ago

Solve by using square root: <br> 4(x-1)^2+2=10

Scilla [17]

$4(x-1)^2+2=10\\\\4(x^2-2x+1)+2-10=0\\\\4 x^2-8x+4+2-10=0\\\\4 x^2-8x-4=0\ \ / :4\\\\x^2-2x-1=0\\\\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{2-\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2-\sqrt{ 8}}{2 }=\frac{2- \sqrt{ 4*2}}{2 }=\\\\=\frac{2-\sqrt{ 8}}{2 }=\frac{2(1- \sqrt{ 2})}{2 }=1- \sqrt{ 2}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{2+\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2(1+ \sqrt{ 2})}{2 }=1+ \sqrt{ 2}$

$Answer:\ x=1- \sqrt{2}\ \ or\ \ x= 1+ \sqrt{ 2}$

3 0

3 years ago

Read 2 more answers

Which matrix can be multiplied to the left of a vector matrix to get a new vector matrix ?

oksano4ka [1.4K]

Answer: The answer is (B).

Step-by-step explanation: We are given four options and we are to select which matrix can be multiplied to the left of a vector matrix to get a new vector matrix. The order of a vector matrix is either n × 1 or 1 × n.

For (A): The order of the matrix is 2 × 1. If we multiply this matrix by a vector matrix of order 1 × 2, then the resulting matrix will be of order 2 × 2, which is not a vector matrix.

For (B): The order of the matrix is 3 × 2. If we multiply this matrix by a vector matrix of order 2 × 1, then the resulting matrix will be of order 3 × 1, which is a new vector matrix.

For (C): The order of the matrix is 2 × 2. If we multiply this matrix by a vector matrix of order 2 × 1, then the resulting matrix will be of order 2 × 1, which is a vector matrix of order same as before.

For (D): The order of the matrix is 1 × 2. If we multiply this matrix by a vector matrix of order 2 × 1, then the resulting matrix will be of order 1 × 1, which is a not vector matrix.

Thus, the correct option is (B).

5 0

3 years ago

Read 2 more answers

Determine the equation of a line through the point (3,-4) that is perpendicular to the line y=3x+7

Lana71 [14]

Answer:

y = - $\frac{1}{3}$ x - 3

Step-by-step explanation:

The equation of a line in slope- intercept fprm is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 7 is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{3}$ , thus

y = - $\frac{1}{3}$ x + c ← is the partial equation of the perpendicular line

To find c substitute (3, - 4) into the partial equation

- 4 = - 1 + c ⇒ c = - 4 + 1 = - 3

y = - $\frac{1}{3}$ x - 3 ← equation of perpendicular line

7 0

2 years ago

3. A woman deposits Php 23,200 into her account. How much would

nikklg [1K]

Answer:

(assuming simple interest)

I'll setup the problem and you can do the computation

Step-by-step explanation:

The formula for simple interest:

I = P*r*t

P = deposits

r = interest rate per period (a year)

t = number of periods

P = Php 23,200

r = 0.06

t = 1

If you have questions, send me a comment

3 0

2 years ago

Help with question 16 ASAP​

Help with question 16 ASAP