(2n+1)(2n-1)(n+5)
=(4n^2+2n-2n-1)(n+5)
=(4n^2-1)(n+5)
=4n^3-n+20n^2-5
4n^3+20n^2-n-5
Answer:
The estimated expense would be about $1000.00 in which taxzation and inflation is unaccounted for.
Step-by-step explanation:
Answer:
13 is two and two thirds of four and seven eighths.
Step-by-step explanation:
To solve this, all you need to do is divide 13 by 2 and two thirds. Let's do it:

Answer:
C) (a-12b)(a+12b)
Step-by-step explanation:
a^2-144b^2 = (a-12b)(a+12b)
This is the formula that when two terms squared are written with a minus sign between them their factors are the product of the original numbers once with a plus sign and once with the minus sign.
This can be explained by multiplying them.
(a-12b)
<u> *(a+12b) </u>
a²- 12ab
<u> +12ab - 144b² </u>
<u> a² +0 - 144b² </u>
We see we get the same answer as applying the formula above.
to get the equation of any straight line, we simply need two points off of it, well, let's use the provided values hmmm

