How many miles of MgCI2 are there in 345 g of the compound?
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Answer:
750g of Aluminum
Assuming 8.6 cm lenth is the height of the cylinder. The volume of a cylinder is: V = *r^2*h
V = 3.14cm x 10.24cm x 3.6cm
V = 280cm^3
Now density = mass/volume
2.7g/cm^3 = mass/280cm^3
2.7g/cm^3 x 280cm^3 = mass/<u>280cm^3</u> x <u>280cm^3</u>
= 750g of Aluminum