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Shkiper50 [21]
3 years ago
15

When the pH of an aqueous solution is 8, what is the OH- ion concentration in moles per liter?

Chemistry
1 answer:
Lilit [14]3 years ago
8 0

Answer:

D. 12 is 1 × 10-6

Explanation:

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If an area has high air pressure and low humidity, what type of weather will it most likely have?
elixir [45]

Aloha~! My name is Zalgo and I am here to help you out today. Those sort of conditions could be fore-boding/foreshadowing/warning that there will soon be a storm or that it will rain quite a lot. In the case of it being a storm, you should be a small room where there are no windows and nothing that is small that will fly towards you that could kill you.

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4 0
3 years ago
Read 2 more answers
Consider a generic redox reaction?
vesna_86 [32]
The Nernst equation allows us to predict the cell potential for voltaic cells under conditions other than the standard conditions of 1M, 1 atm, 25°C. The effects of different temperatures and concentrations may be tracked in terms of the Gibbs energy change ΔG. This free energy change depends upon the temperature & concentrations according to   ΔG = ΔG°  +  RTInQ  where ΔG° is the free energy change under conditions and Q is the thermodynamic reaction quotient. The free energy change is related to the cell potential  Ecell by ΔG= nFEcell

so for non-standard conditions
              -nFEcell = -nFE°cell  + RT InQ

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5 0
3 years ago
Ethene is the first member of the
DanielleElmas [232]
It will be:

b. Alkyne* series

* You have done a spelling mistake here. It will be "Alkene" not  "Alkyne".
5 0
3 years ago
In a chemical equation the sum of the masses
monitta
The sum of the masses of the reactants must equal the sum of the masses of the products; as required by 
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5 0
3 years ago
A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit
Triss [41]

Answer:

The final pressure is approximately 0.78 atm

Explanation:

The original temperature of the gas, T₁ = 263.0 K

The final temperature of the gas, T₂ = 298.0 K

The original volume of the gas, V₁ = 24.0 liters

The final volume of the gas, V₂ = 35.0 liters

The original pressure of the gas, P₁ = 1.00 atm

Let P₂ represent the final pressure, we get;

\dfrac{P_1 \cdot V_1}{T_1} = \dfrac{P_2 \cdot V_2}{T_2}

P_2 = \dfrac{P_1 \cdot V_1 \cdot T_2}{T_1 \cdot V_2}

P_2 = \dfrac{1 \times 24.0 \times 298}{263.0 \times  35.0} = 0.776969038566

∴ The final pressure P₂ ≈ 0.78 atm.

4 0
3 years ago
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