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yan [13]
3 years ago
13

You spot a friend walking on a moving walkway in an airport. You are not on the walkway and you want to keep up with her.

Chemistry
1 answer:
Mademuasel [1]3 years ago
3 0

I think the answer is A.

A. the speed of the walkway multiplied by the speed at which she is walking

The speed she is walking accelerates her speed by the base speed of the walkway.

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What is the volume (in liters) occupied by 49.8 g og HCl at STP
Anon25 [30]

Using ideal gas equation,

P\times V=n\times R\times T

Here,

P denotes pressure

V denotes volume

n denotes number of moles of gas

R denotes gas constant

T denotes temperature

The values at STP will be:

P=1 atm

T=273 K

R=0.0821 atm L mol ⁻¹

Mass of HCl given= 49.8 g

Molar mass of HCl given=36.41

Number of moles of gas, n= \frac{Given mass of the substance}{Molar mass of the substance}

Number of moles of gas, n= \frac{49.8}{36.46}

Number of moles of gas, n= 1.36

Putting all the values in the above equation,

V=\frac{1.36\times 0.0821\times 273}{1}

V=30.6 L

So the volume will be 30.6 L.



6 0
3 years ago
Would an opah fish be better suited to live in cold water or warm water? explain why
Kaylis [27]

Don't blame me if you get it wrong i'm a dumb but yet successful student

Warm blood gives deep-sea fish a boost, according to Wegner. The opah's muscles and nervous system likely function faster than an equivalent fish with cold blood. ... This fish, the southern opah, lives in colder waters than the northern opah, so it would be harder to keep warm, Wegner said — but even more beneficial.

4 0
3 years ago
What are the oxidation numbers of the atoms in this reaction?
ipn [44]
A, B and D should be the ones you should check
8 0
3 years ago
Atoms of elements that are in group 15 with what charge
liq [111]

Answer:

The elements in group 13 and group 15 form a cation with a -3 charge each.

8 0
2 years ago
Calculate the pH of a 0.10 M HCN solution that is 0.0070% ionized.
Anastaziya [24]

Answer:

D) 5.15

Explanation:

Step 1: Write the equation for the dissociation of HCN

HCN(aq) ⇄ H⁺(aq) + CN⁻(aq)

Step 2: Calculate [H⁺] at equilibrium

The percent of ionization (α%) is equal to the concentration of one ion at the equilibrium divided by the initial concentration of the acid times 100%.

α% = [H⁺]eq / [HCN]₀ × 100%

[H⁺]eq = α%/100% × [HCN]₀

[H⁺]eq = 0.0070%/100% × 0.10 M

[H⁺]eq = 7.0 × 10⁻⁶ M

Step 3: Calculate the pH

pH = -log [H⁺] = -log 7.0 × 10⁻⁶ = 5.15

7 0
3 years ago
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