If the enthalpy is positive and the entropy is positive, the Gibbs energy will always be positive, and the reaction will never be feasible.
<h3>What is the Gibbs Free Energy?</h3>
The Gibb Free Energy is used to obtain the feasibility of a reaction. If the Gibbs free energy is positive the reaction is not spontaneous. If the value is negative, the reaction is spontaneous while a zero values indicates equilibrium.
From the equation;
ΔG = ΔH - TΔS, it follows that if the enthalpy is positive and the entropy is positive, the Gibbs energy will always be positive, and the reaction will never be feasible.
Learn more about Gibbs Free energy:brainly.com/question/20358734
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The answer is B. The chlorine has 7 electrons at the outer shell. So it will gain one electron to become stable when forms a chloride ion. And the gained electron will stay at the outer shell. So the radius becomes larger.
Answer: Every enzyme has a specific name that can give us insight into the specific reaction that that enzyme can catalyze. We divide them into six different categories.
1) Oxidoreductase - includes two different types of reactions by transferring electrons from either molecule A to B or vice versa. It is involved in oxidizing electrons away from a molecule.
2) Hydrolase - uses water to divide a molecule into two other molecules.
3) Transferase - you move some functional group X from molecule B to molecule A
4) Ligase - catalyzes reactions between two molecules, A and B, that are combining to form a complex between the two. (example: DNA replication)
5) Lyase - divides a molecule into two other molecules without using water and without reducing or oxidation
<h3>
Answer:</h3>
3.33 mol H₂O
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
60.0 g H₂O (Water)
<u>Step 2: Identify Conversions</u>
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply:
<u>Step 4: Convert</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
3.32963 mol H₂O ≈ 3.33 mol H₂O
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