Let the total toys be x.
The first has (1/10)x = x/10
The third child has one more toys than the first = x/10 + 1
The fourth has double of the third: = 2* (x/10 + 1) = 2x/10 + 2
Since we know that the second child has 12 more toys than the first
Therefore the Second minus First = 12.
First let us find the second.
1st + 2nd + 3rd + 4th = x
x/10 + 2nd + (x/10 + 1) + (2x/10 + 2) = x
2nd + x/10 + x/10 + 1 + 2x/10 + 2 = x
2nd + x/10 + x/10 + 2x/10 + 1 + 2 = x
2nd + 4x/10 + 3 = x
2nd = x - 4x/10 - 3
2nd = 6x/10 - 3
But recall
2nd - 1st = 12
6x/10 - 3 - x/10 = 12
6x/10 - x/10 = 12 + 3
5x/10 = 15
5x = 15 * 10
x = 15*10 /5
x = 30
So there were 30 toys in all.
Answer:
acute: D and E
obtuse: A and F
right: B
straight: C
Step-by-step explanation:
<h2>
Hello!</h2>
The answer is:

<h2>
Why?</h2>
To solve the problem, we need to perform the operations and then, add like terms.
We need to apply the distributive property, which is defined by the following way:

Also, we need to remember how to add like terms. Like terms are terms that share the same exponent and the same variable, for example:

We were able to add only the first two terms since they are like terms, both are sharing the same exponent and the same variable.
So, we are given the expression:

Then, solving we have:

Hence, we have that the answer is:

Have a nice day!