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PIT_PIT [208]
3 years ago
15

Find the indicated area under the curve of the standard normal​ distribution; then convert it to a percentage and fill in the bl

ank. About​ ______% of the area is between zequalsminus3 and zequals3 ​(or within 3 standard deviations of the​ mean).
Mathematics
1 answer:
trapecia [35]3 years ago
8 0

Answer:

About​ 99.74% of the area is between z = -3 and z = 3

Step-by-step explanation:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Area between z = 3 and z = -3

pvalue of z = 3 subtracted by the pvalue of z = -3

z = 3 has a pvalue of 0.9987

z = -3 has a pvalue of 0.0013

0.9987 - 0.0013 = 0.9974

0.9974*100 = 99.74%

About​ 99.74% of the area is between z = -3 and z = 3

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Answer:

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3 years ago
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(Please 75 points if answerd need this is 1 min)
chubhunter [2.5K]

Answer:

(5,-4)

Step-by-step explanation:

If reflected over the x-axis, the quadrilateral would be in the fourth quadrant. N' would be at (1,-1) and P' at (6,-1). To reflect, look at the y-coordinate of the point and turn it to negative. With point Q, it's at (5,4) so we just flip the 4 to -4 and that's our point! (5,-4)

8 0
2 years ago
Pls help I dont know how to do this​
german

Answer:

  • 1. CE = 63
  • 2. x = 16

Step-by-step explanation:

Use proportions to solve.

Corresponding sides have same ratio.

<u>Question 1</u>

  • DE/EG = CE/EF
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  • 21(6x + 3) = 17(8x - 1)
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  • 10x = 80
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<u>Question 2</u>

  • KM/MD = KZ/ZH
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3 years ago
Simplify.<br> -9 -5 -7<br> х<br> Y Z<br> 2 6 3<br> X Y Z
krok68 [10]

Answer:

=  {x}^{ - 11}  {y}^{ - 11}  {z}^{ - 10}

Step-by-step explanation:

= \frac{ {x}^{ - 9} {y}^{ - 5}   {z}^{ - 7} }{ {x}^{2}  {y}^{6} {z}^{3}  }  \\   = {x}^{ - 9 - 2}  {y}^{ - 5   - 6}  {z}^{ - 7 - 3}  \\  =  {x}^{ - 11}  {y}^{ - 11}  {z}^{ - 10}

7 0
3 years ago
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